Multiple choice

How much water is to be added to dilute 10mL of 10N HCI to make it decinormal?

  1. 990mL

  2. 1010mL

  3. 100mL

  4. 1000mL
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A Correct answer
Explanation

Using N1V1 = N2V2: 10N * 10mL = 0.1N * V2. V2 = 100 / 0.1 = 1000mL. Water to be added = 1000mL - 10mL = 990mL.

AI explanation

Using the dilution formula N1V1 = N2V2, we have 10 N times 10 ml equals 0.1 N times the final volume V2. Solving for V2 gives a final volume of 1000 ml. To find the water added, subtract the initial 10 ml of acid from the 1000 ml total volume, which equals 990 ml. The amount of water to be added is 990 ml.

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