Multiple choice

Two liquid A and B are at $32^oC$ and $24^oC$. When mixed in equal masses temperature of mixture is found to be $28^oC$, Their specific heats are in the ratio of

  1. 3:2

  2. 2:3

  3. 1:1

  4. 4:3
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C Correct answer
Explanation

Using the principle of calorimetry, heat lost by hot liquid equals heat gained by cold liquid. m*sA*(32-28) = m*sB*(28-24). This simplifies to 4*sA = 4*sB, so sA/sB = 1/1.

AI explanation

Using the principle of heat exchange, the heat lost by liquid A equals the heat gained by liquid B, giving m * s_A * (32 - 28) = m * s_B * (28 - 24). Substituting the equal masses and the temperature differences simplifies the equation to s_A * 4 = s_B * 4. Therefore, the ratio of their specific heats s_A to s_B is 1:1.

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