Digital Logic and Microprocessors

The reasons given in all of the options are correct. So, this option (All of the above) is the correct answer.

Semaphore variable is accessed by two atomic operations p and v.

These are the correct statements.

One byte instruction includes opcode and operand in the same byte.

Subtract instruction subtracts the specified byte, in a register or in the address contained by the H & L register from the content of the accumulator.

AND instruction performes a logical AND function between the specified byte, either in a register or in the address contained in the H & L register, and the contents of the accumulator.

This mode results in single-byte instruction. The byte contains bits which specifies a register pair, which in turn contains the address of the data in memory.

Auxiliary Carry Flag is set,  if there is a Carry out of bit 3 during an addition or a borrow by bit 3 during a subtraction.

OR is an operation where the output depends on any one of the two condition given, then output is true when any of the two inputs or both of them are true.

Binary Arithmetic Instruction may use any of the addressing modes for one of the operands, but, except when the source operand is immediate, one of the two operands must be a register.

OR is the operation where the output is true when any of the two inputs or both of them were true.

In EX-OR operation, the output is true only when one of the input was true and output is false if both inputs are at the same logic.

All Conditional Branch instructions have the 2 byte machine code format where the second byte gives a 8-bit signed displacement relative to the address of the next instruction in sequence.

In EX-NOR operation, the output is true only when both of the input are true or both the input and output are false if the inputs are at the different logic.