Algebra Questions

Multiple choice
  1. $a > 0$
  2. $-1 < a < 0$
  3. $-1 < a < 1$
  4. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

(a/b + b/a) < 2 => (a^2+b^2)/ab < 2. Since (a-b)^2 >= 0, a^2+b^2 >= 2ab. For the sum to be less than 2, the roots must be complex or have different signs. Discriminant D = 36 - 8a. For real roots, a <= 4.5. The condition (a/b + b/a) < 2 is impossible for real roots of the same sign. Thus, no real 'a' satisfies this.

Multiple choice
  1. $2x^2-3\sqrt 2 x+\dfrac 94=0$
  2. $x^{2}+x-5=0$
  3. $x^{2}+3x+2\sqrt{2}=0$
  4. $5x^{2}-3x+1=0$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

A quadratic equation has two distinct real roots if its discriminant D = b^2 - 4ac > 0. For B, x^2 + x - 5 = 0, D = 1^2 - 4(1)(-5) = 21, which is greater than 0.

Multiple choice
  1. Real and Distinct Roots

  2. Real and Equal Roots

  3. Imaginary Roots

  4. None of the above

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The discriminant D of the quadratic equation ax^2 + bx + c = 0 is b^2 - 4ac. For 3x^2 + 4x + 1 = 0, D = 4^2 - 4(3)(1) = 16 - 12 = 4. Since D > 0, the roots are real and distinct.

Multiple choice
  1. real and unequal

  2. real and equal

  3. imaginary

  4. none of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The discriminant of the quadratic equation ax^2 + bx + c = 0 is D = b^2 - 4ac. For 3x^2 - 4x + 3 = 0, D = (-4)^2 - 4(3)(3) = 16 - 36 = -20. Since the discriminant is negative, the roots are imaginary.