Multiple choice ............... is true for discriminate of quadratic equation $x^2 + x + 1 = 0$. D = 0 D < 0 D > 0 D is a perfect square Reveal answer Fill a bubble to check yourself B Correct answer Explanation For x^2 + x + 1 = 0, the discriminant is D = b^2 - 4ac = 1 - 4 = -3. Therefore, D < 0. AI explanation AI 1 The discriminant of a quadratic equation ax^2 + bx + c = 0 is given by the formula D = b^2 - 4ac. Substituting the values from x^2 + x + 1 = 0 gives D = (1)^2 - 4(1)(1) = 1 - 4 = -3. Because -3 is less than zero, D < 0. Thanks Wrong explanation