Sum of roots of the quadratic equation $5-3{ x }^{ 2 }+7x=0$ will be:
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Sum of roots of the quadratic equation $5-3{ x }^{ 2 }+7x=0$ will be:
The equation is -3x^2 + 7x + 5 = 0. The sum of the roots is -b/a = -7 / -3 = 7/3.
Rearrange the equation into standard form to get negative 3x squared plus 7x plus 5 equals 0. The sum of the roots is given by the formula negative b divided by a. Substituting the values gives negative 7 divided by negative 3, which simplifies to 7/3.