Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

Five years hence, father's age will be three times the age of his son. Five years ago, father was seven times as old as his son. Find their present ages
  1. Father's age $= 80$ years, Son's age $= 25$ years
  2. Father's age $= 60$ years, Son's age $= 30$ years
  3. Father's age $= 75$ years, Son's age $= 42$ years
  4. Father's age $= 40$ years, Son's age $= 10$ years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let F and S be present ages. (F+5) = 3(S+5) => F - 3S = 10. (F-5) = 7(S-5) => F - 7S = -30. Subtracting equations: 4S = 40, so S = 10. Then F = 40.

Multiple choice

Five years hence, the age of jacob will be three times that of his son. Five years ago, Jacob's age was seven times that of his son. What are their present ages?
  1. Present age of Jacob: $50$ years and Present age of Jacob's son: $15$ years
  2. Present age of Jacob: $50$. years and Present age of Jacob's son: $10$ years
  3. Present age of Jacob: $40$ years and Present age of Jacob's son: $10$ years
  4. Present age of Jacob: $35$  years and Present age of Jacob's son: $15$ years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let J be Jacob's age, S be son's age. (J+5) = 3(S+5) => J = 3S + 10. (J-5) = 7(S-5) => J = 7S - 30. 3S + 10 = 7S - 30 => 4S = 40 => S = 10. J = 40.

Multiple choice

Twice the son's age in years is added to the father's age, the sum is $70$. But if twice the father's age is added to the son's age, the sum is $95$. Then the ages of father and son respectively are
  1. $30$ yrs, $10$ yrs
  2. $40$ yrs, $15$ yrs
  3. $45$ yrs, $20$ yrs

  4. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let F be father's age and S be son's age. 2S + F = 70 and 2F + S = 95. Multiply the first by 2: 4S + 2F = 140. Subtract the second: 3S = 45, so S = 15. Then F = 70 - 2(15) = 40.

Multiple choice

Solve the following puzzles using the equations: The present age of Beena is 2 years more than Reeta.The present age of Teena is 3 years more than Beena.If the sum of the ages of Reeta , Beena , and Teena is 79 years, find the present age of all the three of them.

  1. Reeta 24 years , Beena 26 years , Teena 29 years.

  2. Reeta 24 years , Beena 21 years , Teena 29 years.

  3. Reeta 24 years , Beena 29 years , Teena 29 years.

  4. Reeta 24 years , Beena 26 years , Teena 30 years.
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The sample space for two dice is 36 outcomes. Outcomes with sum >= 10: (4,6), (5,5), (6,4), (5,6), (6,5), (6,6). There are 6 such outcomes. Probability = 6/36 = 1/6.

Multiple choice

The ages of Hari and Harry are in the ratio $5:7$. If four years from now, the ratio of their ages will be $3:4$, then the present age of
  1. Hari is $20$ years and Harry is $28$ years.
  2. Hari is $28$ years and Harry is $20$ years.
  3. Hari is $25$ years and Harry is $35$ years.
  4. Hari is $35$ years and Harry is $25$ years.
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Hari's age be 5x and Harry's be 7x. Four years later, (5x+4)/(7x+4) = 3/4. Solving this gives 20x + 16 = 21x + 12, so x = 4. Thus, Hari is 20 and Harry is 28.