Multiple choice

Solve the following puzzles using the equations: The present age of Beena is 2 years more than Reeta.The present age of Teena is 3 years more than Beena.If the sum of the ages of Reeta , Beena , and Teena is 79 years, find the present age of all the three of them.

  1. Reeta 24 years , Beena 26 years , Teena 29 years.

  2. Reeta 24 years , Beena 21 years , Teena 29 years.

  3. Reeta 24 years , Beena 29 years , Teena 29 years.

  4. Reeta 24 years , Beena 26 years , Teena 30 years.
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A Correct answer
Explanation

The sample space for two dice is 36 outcomes. Outcomes with sum >= 10: (4,6), (5,5), (6,4), (5,6), (6,5), (6,6). There are 6 such outcomes. Probability = 6/36 = 1/6.

AI explanation

Let Reeta's present age be x years. According to the problem, Beena's age is x + 2 and Teena's age is x + 2 + 3, which equals x + 5. The sum of their ages is x + x + 2 + x + 5 = 79, which simplifies to 3x + 7 = 79, so 3x = 72 and x = 24. Therefore, Reeta is 24 years old, Beena is 26 years old, and Teena is 29 years old.

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