Multiple choice

Two years ago, a father was five times as old as his son. Two years later, his age will be $8$ more than $3$ times the age of the son. Find the present ages of father.

  1. $22$ years
  2. $60$ years
  3. $39$ years
  4. $42$  years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let F and S be present ages. (F-2) = 5(S-2) => F = 5S - 8. (F+2) = 3(S+2) + 8 => F = 3S + 12. Equating: 5S - 8 = 3S + 12 => 2S = 20 => S = 10. F = 5(10) - 8 = 42.