Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

Two years ago, the age of Rajan was 4 times that of his son. After 5 years, the ratio of ages of Rajan to his son will be 5:2. What is the present age of his son?

  1. 8 years

  2. 14 years

  3. 7 years

  4. 9 years

  5. None of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let Rajan's age be R and son's be S. Two years ago: (R-2) = 4(S-2). After 5 years: (R+5)/(S+5) = 5/2. Solving the system: R-2 = 4S-8 => R = 4S-6. Substitute into second: (4S-6+5)/(S+5) = 5/2 => (4S-1)/(S+5) = 5/2 => 8S-2 = 5S+25 => 3S = 27 => S = 9.

Multiple choice

10 years ago, the average age of a family of 4 members was 24 years. The present average age of the family is same but 2 children have been born in between. The age difference between those two children is two. The ages of the children are,

  1. 3, 5

  2. 5, 8

  3. 4, 2

  4. 6, 3

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

10 years ago, sum of ages = 4 * 24 = 96. Today, those 4 members are 10 years older each, so 96 + 40 = 136. Current average is 24 for 6 members (4 adults + 2 children), so total age = 6 * 24 = 144. Sum of children's ages = 144 - 136 = 8. Since difference is 2, children are 3 and 5.

Multiple choice

The average of present ages of members of a family (Father, Mother and son) is 34. 4 years hence, the son's age is half of the mother's age. 10 years ago, the ratio of ages of father and son is 17: 4. Find the sum of ages of father and mother at the time of son's birth.

  1. 45 years

  2. 50 years

  3. 52 years

  4. 48 years

  5. 49 years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let F, M, S be current ages. (F+M+S)/3 = 34 => F+M+S = 102. (S+4) = 0.5(M+4) => M = 2S + 4. (F-10)/(S-10) = 17/4 => 4F - 40 = 17S - 170 => 4F = 17S - 130. Substituting M: F + 2S + 4 + S = 102 => F = 98 - 3S. 4(98 - 3S) = 17S - 130 => 392 - 12S = 17S - 130 => 29S = 522 => S = 18. Then M = 40, F = 44. At son's birth (18 years ago), Father was 26, Mother was 22. Sum = 48.

Multiple choice

In each of the following questions, read the given statement and compare the Quantity I and Quantity II on its basis. (only quantity is to be considered) Quantity I : On May 1, 2010, the ratio of the age of A to B was 5 : 6. On May 1, 2018, the ratio of the age of A to B became 19 : 22. On Dec 1, 2018, what will be the age of B? Quantity II : 44.5 years

  1. Quantity : I > Quantity : II

  2. Quantity : I ≥ Quantity : II

  3. Quantity : I < Quantity : II

  4. Quantity : II ≥ Quantity : I

  5. Quantity I = Quantity II or relation can't be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

A/B = 5/6 in 2010. A = 5x, B = 6x. In 2018 (8 years later), (5x+8)/(6x+8) = 19/22. 22(5x+8) = 19(6x+8). 110x + 176 = 114x + 152. 4x = 24, x = 6. In 2018, B = 6(6) + 8 = 44. By Dec 2018, B is 44 + 7/12 = 44.58. Quantity I (44.58) > Quantity II (44.5).

Multiple choice

The ratio of age of Subash five years ago to age of Dinesh five years ago is 2: 3. The ratio of age of Dinesh five years hence to age of Naveena five years hence is 8: 9. If Naveena is 15 years elder than Subash, find the present age of Dinesh.

  1. 25 years

  2. 30 years

  3. 35 years

  4. 40 years

  5. 20 years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let ages 5 years ago be S-5 = 2k, D-5 = 3k. Let ages 5 years hence be D+10 = 8m, N+10 = 9m. Solving the system with N = S + 15 leads to D = 35.

Multiple choice

The average age of Mr. And Mrs Bachchan at the time of their marriage in 1972 was 23 years. On the occasion of their anniversary in 1976, they observed that the average age of their family had come down by 4 years compared to the average age at the time of their marriage. This was due to the fact that their son Abhishek was born during that period. What was the age of Abhishek in 1980? (Family consists of the trio mentioned )

  1. 5

  2. 6

  3. 7

  4. 8
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In 1972, average age of 2 was 23, sum = 46. In 1976, they are 4 years older, sum = 46 + 8 = 54. The family (3 people) has an average age 4 years less than the 1972 average (23 - 4 = 19). Total age in 1976 = 19 * 3 = 57. Abhishek's age in 1976 = 57 - 54 = 3. In 1980, he is 3 + 4 = 7.

Multiple choice

The age of the boy is one-fifth of the age of his mother and sum of the ages of the son and the mother is equal to the age of the father. After 15 years, the sum of the ages of the son and his mother will be four-third of his father's age. Find the ratio of the present ages of son, mother and father, respectively.

  1. 1 : 5 : 7

  2. 2 : 10 : 10

  3. 1 : 5 : 6

  4. 2 : 8 : 9
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let son = S, mother = M, father = F. S = M/5, so M = 5S. S + M = F, so F = 6S. After 15 years: (S + 15) + (M + 15) = (4/3)(F + 15). Substitute M=5S, F=6S: 6S + 30 = (4/3)(6S + 15) = 8S + 20. 2S = 10, S = 5. Then M = 25, F = 30. Ratio S:M:F = 5:25:30 = 1:5:6.

Multiple choice

The sum of ages of two brothers two years agowas 40 years. The ratio of their ages after four yearswould be 8: 5. Find their present ages.

  1. 24 years and 12 years

  2. 32 years and 22 years

  3. 36 years and 24 years

  4. 28 years and 16 years

  5. 20 years and 8 years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Two years ago, the brothers' total age was 40, so their present total is 44 and their total after four years is 52. If their ages then were 8k and 5k, 13k = 52 gives k = 4. Their present ages were therefore 28 and 16 years.