Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

I am the eldest child of my parents. There is a gap of 6 years between the ages of my brother and sister including myself. If my mother was 22 years, when I was born? What was my age at the birth of her youngest child?

  1. 30

  2. 28

  3. 12

  4. 25
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The eldest child is the narrator, and the three children are separated by 6 years, so the youngest is 12 years younger. Since the mother was 22 when the narrator was born, the narrator is 12 when the youngest child is born.

Multiple choice

Directions: The following question consists of two quantities, Quantity I and Quantity II. You are to compare the two quantities and find the correct relationship between both the quantities. Present ages of Ram and Ghanshyam differ by 16 years. 6 years ago, Ram was 3 times as old as Ghanshyam. Quantity I: Present age of Ghanshyam Quantity II: 16 years

  1. Quantity I > Quantity II

  2. Qantity I < Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II, or No relation
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let R and G be present ages. R - G = 16. Six years ago: (R-6) = 3(G-6). Substituting R = G + 16: (G+16-6) = 3G - 18, so G+10 = 3G - 18, 2G = 28, G = 14. Quantity I is 14, Quantity II is 16. Thus, I < II.

Multiple choice

If the current age of a brother exceeds twice the age of his sister by three years, and the age difference between them is 5 years, what will be the ratio of the ages of the brother and the sister five years from now?

  1. 7 : 12

  2. 12 : 7

  3. 9 : 13

  4. 13 : 9

  5. 13 : 10
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let sister be S and brother be B. B = 2S + 3 and B - S = 5. Substituting B = S + 5 into the first equation: S + 5 = 2S + 3, so S = 2 and B = 7. Five years from now, ages are 7+5=12 and 2+5=7. Ratio is 12:7.

Multiple choice

Twelve years ago, the ratio of the ages of Sarah and John was 4 : 5. If the present ratio of their ages is 7 : 8, then how much older is the older person compared to the younger person?

  1. 2 years

  2. 3 years

  3. 4 years

  4. 5 years

  5. 6 years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the ages 12 years ago be 4x and 5x. Their present ages are 4x+12 and 5x+12. The ratio (4x+12)/(5x+12) = 7/8 leads to 32x + 96 = 35x + 84, so 3x = 12 and x = 4. The present ages are 28 and 32, with a difference of 4 years.

Multiple choice

Five years ago, Nuri was thrice as old as Sonu. After ten years from now, Nuri will be twice as old as Sonu. Present ages of Nuri and Sonu respectively are 1. 40 years, 20 years 2.30 years, 20 years 3. 20 years, 50 years 4. 50 years, 20 years

  1. 1

  2. 2

  3. 3

  4. 4
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let N and S be present ages. 5 years ago: (N-5) = 3(S-5). 10 years later: (N+10) = 2(S+10). From first: N = 3S - 10. Substitute into second: 3S - 10 + 10 = 2S + 20. 3S = 2S + 20, so S = 20. Then N = 3(20) - 10 = 50.