At a family gathering, the current ages (in years) of four siblings, Emma, Liam, Mia, and Noah, are four consecutive even integers. Four years ago, the sum of their ages was 36 years. What is the present age (in years) of the youngest sibling, Emma?

Let the four consecutive even integers representing the present ages be x, (x + 2), (x + 4), and (x + 6). Four years ago, the sum of their ages was (x - 4) + (x - 2) + x + (x + 2) = 36. Combining like terms gives 4x - 4 = 36, which simplifies to 4x = 40 and yields x = 10. Therefore, Emma's present age is 10 years.

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