Multiple choice

10 years ago, the average age of a family of 4 members was 24 years. The present average age of the family is same but 2 children have been born in between. The age difference between those two children is two. The ages of the children are,

  1. 3, 5

  2. 5, 8

  3. 4, 2

  4. 6, 3

  5. None of these
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A Correct answer
Explanation

10 years ago, sum of ages = 4 * 24 = 96. Today, those 4 members are 10 years older each, so 96 + 40 = 136. Current average is 24 for 6 members (4 adults + 2 children), so total age = 6 * 24 = 144. Sum of children's ages = 144 - 136 = 8. Since difference is 2, children are 3 and 5.

AI explanation

Ten years ago the total age was 4 times 24, which equals 96, making the current total age of the original four members 136. The current average of all six members remains 24, meaning the new total age is 6 times 24, or 144. The combined age of the two children is 144 minus 136, which equals 8. Letting the younger child be x and the older be x + 2, the equation is 2x + 2 = 8, so 2x = 6 and x = 3. The ages of the two children are 3 and 5.

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