Multiple choice

Two years ago, Dilip was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. The present ages of son and Dilip are

  1. 14, 38 years

  2. 16, 40 years

  3. 12, 36 years

  4. None
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let D and S be present ages. Two years ago: D-2 = 3(S-2). Two years hence: 2(D+2) = 5(S+2). D-2 = 3S-6 => D = 3S-4. 2(3S-4+2) = 5S+10 => 6S-4 = 5S+10 => S = 14. D = 3(14)-4 = 38.

AI explanation

Let the son's present age be s and Dilip's be d; two years ago the equation is d - 2 = 3(s - 2). Two years hence the equation is 2(d + 2) = 5(s + 2). Substituting d = 3s - 4 into the second equation gives 2(3s - 2) = 5s + 10, which simplifies to 6s - 4 = 5s + 10, so s = 14. Dilip's age is 3 times 14 minus 4, which equals 38, so the ages are 14 and 38.

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