Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and choose the correct option. $I. (x^2 - x - 2 = 0)$ $II. (y^2 + 3y + 2 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving equation I: x² - x - 2 = 0 gives x = 2 or x = -1. Solving equation II: y² + 3y + 2 = 0 gives y = -2 or y = -1. Comparing all values: 2 > -2, 2 > -1, -1 > -2, and -1 = -1. In all cases, x ≥ y (x is greater than or equal to y). Therefore option B is correct.

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