Multiple choice

In each question two equations numbered I and II are given, you have to solve both the equation and choose the correct answer. $I. (x^2 - 40x + 391 = 0)$ $II. (y^2 - 8y - 345 = 0)$

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \le y\)$
  4. $\(x \ge y\)$

  5. x = y or the relationship can’t be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation I: x² - 40x + 391 = 0 factors to (x-17)(x-23) = 0, so x = 17 or 23. Solving equation II: y² - 8y - 345 = 0 gives y = (8 ± √1444)/2 = (8 ± 38)/2, so y = 23 or -15. When x = 17, we have 17 > -15 but 17 < 23. When x = 23, we have 23 > -15 and 23 = 23. Since x can be less than, greater than, or equal to y depending on which values are chosen, the relationship cannot be established.

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