Multiple choice

In the following question two equations numbered I and II are given. You have to solve both the equations and choose the correct option.\newline I. (x^2 - 40x + 396 = 0)\newline II. (15y^2 + 19y - 8 = 0)

  1. x > y

  2. x < y

  3. x ≥ y

  4. x ≤ y

  5. x = y or relation can’t be established.
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A Correct answer
Explanation

Solving x² - 40x + 396 = 0 gives x = 18 or 22. Solving 15y² + 19y - 8 = 0 gives y = 1/3 or -8/5. Both x values (18, 22) are greater than both y values (0.33, -1.6), so x > y is correct.

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