Multiple choice

In each question two equations numbered I and II are given, you have to solve both the equation and choose the correct answer.(I. x^2 + 9x + 20 = 0 ) (II. y^2 - 16 = 0)

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \le y\)$
  4. $\(x \ge y\)$

  5. X = Y or the relationship can’t be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation I: x² + 9x + 20 = 0 gives x = -4, -5. Solving equation II: y² - 16 = 0 gives y = 4, -4. Comparing all values: x = -4 equals y = -4; in all other cases x is less than y. Therefore x ≤ y is always true.

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