Tag: programming languages

Questions Related to programming languages

class Dog { public static void bark() { System.out.print("woof "); }}class Alsation extends Dog { public static void bark() { }}public class Bark { public static void main(String args[]) { Dog woofer = new Dog(); Dog nipper = new Alsation(); woofer.bark(); nipper.bark(); }}What is the output
technology programming languages

  1. woof

  2. woof woof

  3. Nothing will be printed as output

  4. None of the above

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Correct Option: B

Destructors can be overloaded.

technology programming languages

  1. True

  2. False

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Correct Option: B

public class test08 { public test08(Object o) { System.out.println("Object"); } public test08(double[] dArray) { System.out.println("double array"); } public static void main(String[] args) { new test08(null); } }
technology programming languages

  1. Object

  2. double array

  3. Compile Error

  4. None of the above

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Correct Option: B

Storage area with associated semantics is called
technology programming languages

  1. Class

  2. Constructor

  3. Object

  4. None

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Correct Option: C

#include class NewInt { int num; public: NewInt(int n=0):num(n) {printf("cons\n");} int getInt() const {return num;} void setInt(int n){num =n;} ~NewInt(){printf("Dest\n");} }; int main() { NewInt a[5]; for(int i=0;i<=5;i++) a[i].setInt(i+10); for(int i=0;i<=5;i++) printf("%d\n",a[i].getInt()); return 0; } What does the above code snippet do?

technology programming languages

  1. It creates an array of classes

  2. Gives compile time error

  3. It creates an array of objects

  4. It does nothing

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Correct Option: C

Which of the following operators cannot be overloaded?
technology programming languages

  1. ?:(Ternary Operator)

  2. .(member access)

  3. () (Paranthesis)

  4. ::(scope resolution)

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Correct Option: A,B,D

Which of the following cannot be inherited?
technology programming languages

  1. private member

  2. Constructor

  3. Destructor

  4. Overloaded assignment operator

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Correct Option: B,C,D

What happens when the following code is compiled and run. Select the one correct answer. for(int i = 1; i < 3; i++) for(int j = 3; j >= 1; j--) assert i!=j : i;
technology programming languages

  1. The class compiles and runs, but does not print anything.

  2. The number 1 gets printed with AssertionError

  3. The number 2 gets printed with AssertionError

  4. The number 3 gets printed with AssertionError

  5. The program generates a compilation error.

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Correct Option: B
  1. interface I{ void f1(); // 1 public void f2(); // 2 protected void f3(); // 3 private void f4(); // 4 } which lines generate compile time errors?
technology programming languages

  1. compiletime error at lines 1,2,3,4

  2. compiletime error at line 3

  3. compiletime error at line 1

  4. compiletime error at lines 3,4

  5. None of the above

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Correct Option: D

class C1 { static interface I { static class C2 { } } public static void main(String a[]) { C1.I.C2 ob1=new C1.I.C2(); System.out.println("object created"); } } What is the result of attempting to compile and run the program?

technology programming languages

  1. prints object created

  2. Compile time error

  3. Runtime Excepion

  4. None of the above

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Correct Option: A