To answer this question, let's go through each option to understand why it is correct or incorrect:
Option A) The class compiles and runs, but does not print anything. - This option is incorrect. The code contains an assertion statement that will throw an AssertionError if the condition specified in the assertion is false. Since the condition i != j
evaluates to false when i
is equal to j
, an AssertionError will be thrown.
Option B) The number 1 gets printed with AssertionError - This option is correct. The code contains an assertion statement assert i != j : i;
. When i
is equal to j
(as is the case when i
is 1 and j
is also 1), the assertion condition evaluates to false, and an AssertionError is thrown. The value of i
(which is 1) is included in the AssertionError message.
Option C) The number 2 gets printed with AssertionError - This option is incorrect. The code does not reach the point where i
is equal to 2, so this option is not possible.
Option D) The number 3 gets printed with AssertionError - This option is incorrect. The code does not reach the point where i
is equal to 3, so this option is not possible.
Option E) The program generates a compilation error - This option is incorrect. The code does not contain any syntax errors, so it will compile successfully.
The correct answer is Option B) The number 1 gets printed with AssertionError. This option is correct because the assertion condition i != j
evaluates to false when i
is equal to j
, and an AssertionError is thrown with the value of i
(which is 1) included in the message.