Tag: programming languages

Questions Related to programming languages

C++ does not support string type.
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  1. True

  2. False

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Correct Option: A

C++ requires that you re-declare static data members outside the class. This is not required in Java.
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  1. True

  2. False

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Correct Option: A

Expanstion of LISP ....
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  1. List Programming

  2. LISt Programming

  3. List Instruction Set Programming

  4. List Information Set Programming

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Correct Option: B

Expansion of COBOL ....
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  1. Common Object Business Oriented Language

  2. Complete Object Business Oriented Language

  3. Common Object BASIC Oriented Language

  4. Common Oriented Business Object Language

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Correct Option: A

Expansion of FORTRAN ....
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  1. FORmula TRANslation

  2. FORmula TRANslator

  3. FORmal TRANslation

  4. FORmal TRANslator

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Correct Option: B

Expansion of BASIC ......

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  1. Begin All Program Symbolic Instruction Code

  2. Beginners' All-purpose Symbolic Information Code

  3. Beginners' All-purpose System Instruction Code

  4. Beginners' All-purpose Symbolic Instruction Code

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Correct Option: D

You have the following code in a file called Test.java class Base{ public static void main(String[] args){ System.out.println("Hello"); } } public class Test extends Base{} What will happen if you try to compile and run this?

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  1. It will fail to compile.

  2. Runtime error

  3. Compiles and runs with no output.

  4. Compiles and runs printing "Hello"

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Correct Option: D

What is the result of trying to compile and run the following code. public final static void main(String[] args){ double d = 10.0 / -0; if(d == Double.POSITIVE_INFINITY) System.out.println("Positive infinity"); else System.out.println("Negative infinity"); }

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  1. output Positive infinity

  2. output Negative infinity

  3. Will fail to compile

  4. Runtime exception

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Correct Option: A

What is the result that will be printed out ? void aMethod() { float f = (1 / 4) * 10; int i = Math.round(f); System.out.println(i); }

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  1. 2

  2. 0

  3. 3

  4. 2.5

  5. 25

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Correct Option: B

AI Explanation

To determine the result that will be printed out, let's go through the code step by step:

  1. The expression (1 / 4) is evaluated. Since both 1 and 4 are integers, integer division is performed. In integer division, the result is the quotient without any remainder. So, 1 / 4 will evaluate to 0.

  2. The expression 0 * 10 is evaluated. Multiplying any number by 0 will always result in 0.

  3. The variable f is assigned the value of 0.

  4. The Math.round() function is called with f as the argument. The Math.round() function rounds the floating-point value to the nearest integer. In this case, since f is 0, it remains unchanged.

  5. The value of i is assigned the rounded value of f, which is still 0.

  6. Finally, the value of i is printed using System.out.println(i). So, the output will be 0.

Therefore, the correct answer is B) 0.

Which of the following are valid declarations?

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  1. int i = 0XCAFE;

  2. boolean b = 0;

  3. char c = A;

  4. byte b = 128;

  5. char c = "A";

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Correct Option: A

AI Explanation

To determine which of the given options are valid declarations, let's analyze each option:

A. int i = 0XCAFE; This option is a valid declaration. In Java, the prefix "0X" indicates a hexadecimal value. The hexadecimal value 0XCAFE is a valid integer value.

B. boolean b = 0; This option is not a valid declaration. In Java, the boolean data type can only have two possible values: true or false. Assigning an integer value of 0 to a boolean variable is not allowed.

C. char c = A; This option is not a valid declaration. In Java, character literals should be enclosed in single quotes (''). The character literal 'A' represents the character 'A', so the correct declaration would be char c = 'A';.

D. byte b = 128; This option is not a valid declaration. In Java, the byte data type can hold values from -128 to 127. Assigning the value 128 to a byte variable exceeds the range of valid values.

E. char c = "A"; This option is not a valid declaration. In Java, character literals should be enclosed in single quotes (''). The double quotes ("") are used for string literals. To assign the character 'A' to a char variable, the correct declaration would be char c = 'A';.

Therefore, the valid declaration among the given options is A) int i = 0XCAFE.