Tag: technology

Questions Related to technology

How many bytes does a S9(7) COMP-3 field occupy
technology mainframe

  1. 4

  2. 8

  3. 3

  4. 7

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Correct Option: A

How many bytes does a S9(7) SIGN TRAILING SEPARATE field occupy ?
technology mainframe

  1. 7

  2. 8

  3. 9

  4. 4

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Correct Option: B

What is the maximum value that can be stored in S9(8) COMP?
technology mainframe

  1. 999999999

  2. 9999999

  3. 99999999

  4. 99999

Show answer
Correct Option: C
Explanation:

To solve this question, the user needs to know the format and properties of a S9(8) COMP data type in mainframe systems.

The S9(8) COMP is a signed 4-byte (32-bit) binary integer data type in IBM mainframe systems. It can store values ranging from -2147483648 to 2147483647. Since S9(8) is a signed data type, the first bit of the binary representation is reserved for the sign of the number (0 for positive and 1 for negative).

To find the maximum value that can be stored in S9(8) COMP, we can use the formula:

Maximum value = (2^(number of bits - 1)) - 1

For S9(8) COMP, the number of bits is 32 (4 bytes x 8 bits per byte), so the formula becomes:

Maximum value = (2^(32 - 1)) - 1

Maximum value = 2,147,483,647

However, since S9(8) COMP is a signed data type, the maximum positive value that can be stored is half of the range, or 2,147,483,647 / 2 = 1,073,741,823.

Now, let's go through each option and explain why it is right or wrong:

A. 999999999: This option is incorrect because the maximum positive value that can be stored in S9(8) COMP is 1,073,741,823, which is less than 999,999,999.

B. 9999999: This option is incorrect because it is less than the maximum positive value that can be stored in S9(8) COMP, which is 1,073,741,823.

C. 99999999: This option is incorrect because it is greater than the maximum positive value that can be stored in S9(8) COMP, which is 1,073,741,823.

D. 99999: This option is incorrect because it is much less than the maximum positive value that can be stored in S9(8) COMP, which is 1,073,741,823.

Therefore, the correct answer is:

The Answer is: C. 99999999

What is the maximum size of a 01 level item in COBOL II?

technology mainframe

  1. 16777215

  2. 16777200

  3. 1677250

  4. 16772150

Show answer
Correct Option: A

AI Explanation

To answer this question, you need to have an understanding of the COBOL II programming language.

In COBOL II, the maximum size of a 01 level item is determined by the PIC clause. The PIC clause defines the data type and length of the item.

The PIC X clause is used to define alphanumeric data. Each character occupies one byte of storage. Therefore, the maximum size of a 01 level item defined with PIC X is determined by the maximum number of bytes that can be allocated for a single item.

In COBOL II, the maximum number of bytes that can be allocated for a single item is 16,777,215 bytes. This corresponds to option A.

Let's go through each option to understand why they are correct or incorrect:

Option A) 16777215 - This option is correct because it represents the maximum number of bytes that can be allocated for a 01 level item in COBOL II.

Option B) 16777200 - This option is incorrect because it does not represent the maximum number of bytes that can be allocated for a 01 level item in COBOL II.

Option C) 1677250 - This option is incorrect because it does not represent the maximum number of bytes that can be allocated for a 01 level item in COBOL II.

Option D) 16772150 - This option is incorrect because it does not represent the maximum number of bytes that can be allocated for a 01 level item in COBOL II.

The correct answer is option A. This option is correct because it represents the maximum size of a 01 level item in COBOL II.

What is the output of the following code when compiled and run? Select two correct answers. public class Question01 { public static void main(String[] args){ int y=0; //line 1 int x=z=1; //line 2 System.out.println(y+","+x+","+z); //line 3 } }
technology programming languages

  1. Prints 0,1,1

  2. Error during compilation at line 1

  3. E. Error during compilation at line 2

  4. Error during compilation at line 3

Show answer
Correct Option: C,D

What is the output of the following code when compiled and run? Select one correct answer. public class Question02 { public static void main(String[] args){ int j = 017; int i = (byte)j >> 2; //line 1 System.out.println(Integer.toBinaryString(i)); //line 2 } }
technology programming languages

  1. Prints 3

  2. Error during compilation at line 1

  3. Prints 11

  4. Prints 0

Show answer
Correct Option: C

What is the output of the following code when compiled and run? Select one correct answer. import java.io.*; public class Question05 { public static void main(String[] args) { Question05Sub myref = new Question05Sub(); try{ myref.test(); }catch(IOException ioe){} } void test() throws IOException{ System.out.println("In Question05"); throw new IOException(); } } class Question05Sub extends Question05 { void test() { System.out.println("In Question05Sub"); } }
technology programming languages

  1. Prints: In Question05Sub

  2. Prints: In Question05

  3. Prints:In Question05In Question05Sub

  4. The code does not compile.

Show answer
Correct Option: D

How can we create TYPE1 mappings?
technology platforms and products

  1. Using slowly changing dimension wizard

  2. Manually

  3. Both

  4. None of these

Show answer
Correct Option: C

Select three correct statements about the following code. public class Question20 { public static void main(String[] args) { Question20 myref = new Question20Sub(); try{ myref.test(); }catch(Exception e){} } void test() throws Exception{ System.out.println("In Question20"); throw new Exception(); } } class Question20Sub extends Question20 { void test() { System.out.println("In Question20Sub"); } }
technology programming languages

  1. The try-catch block that encloses myref.test(); is mandatory for the code to compile.

  2. Prints: In Question20

  3. Prints: In Question20Sub

  4. Method test() in class Question20Sub has no obligation to declare a throws clause.

  5. An exception is thrown at runtime.

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Correct Option: A,C,D

What is the output of the following code when compiled and run? Select one correct answer. public class Question41{ public static void main(String[] args){ Object[] obj = new Object[3]; for(int i=0;i
technology programming languages

  1. Compilation error.

  2. Prints: 1 3 4 true false true

  3. Prints: 1 2 4 false false true

  4. Prints: 3 4 true true true

  5. None of the above.

Show answer
Correct Option: C