Tag: technology

Questions Related to technology

How many bytes does a S9(7) COMP-3 field occupy

technology mainframe

  1. 4

  2. 8

  3. 3

  4. 7

Show answer
Correct Option: A

AI Explanation

To answer this question, we need to understand the representation of a COMP-3 field in COBOL.

A S9(7) COMP-3 field is a signed numeric field that can hold up to 7 digits. It is stored in a packed decimal format, where each digit is represented by half a byte (nibble). The left-most nibble is used to store the sign of the number.

In a COMP-3 field, each digit occupies 4 bits (half a byte). Therefore, for a S9(7) COMP-3 field, we have 7 digits, which requires 7*4 = 28 bits.

Since 8 bits make up 1 byte, we need to divide 28 bits by 8 to get the number of bytes required.

28 bits / 8 = 3.5 bytes

Since we cannot have half a byte, we need to round up to the nearest whole number. Therefore, a S9(7) COMP-3 field occupies 4 bytes.

So, the correct answer is A) 4 bytes.

How many bytes does a S9(7) SIGN TRAILING SEPARATE field occupy ?

technology mainframe

  1. 7

  2. 8

  3. 9

  4. 4

Show answer
Correct Option: B

What is the maximum value that can be stored in S9(8) COMP?

technology mainframe

  1. 999999999

  2. 9999999

  3. 99999999

  4. 99999

Show answer
Correct Option: C
Explanation:

To solve this question, the user needs to know the format and properties of a S9(8) COMP data type in mainframe systems.

The S9(8) COMP is a signed 4-byte (32-bit) binary integer data type in IBM mainframe systems. It can store values ranging from -2147483648 to 2147483647. Since S9(8) is a signed data type, the first bit of the binary representation is reserved for the sign of the number (0 for positive and 1 for negative).

To find the maximum value that can be stored in S9(8) COMP, we can use the formula:

Maximum value = (2^(number of bits - 1)) - 1

For S9(8) COMP, the number of bits is 32 (4 bytes x 8 bits per byte), so the formula becomes:

Maximum value = (2^(32 - 1)) - 1

Maximum value = 2,147,483,647

However, since S9(8) COMP is a signed data type, the maximum positive value that can be stored is half of the range, or 2,147,483,647 / 2 = 1,073,741,823.

Now, let's go through each option and explain why it is right or wrong:

A. 999999999: This option is incorrect because the maximum positive value that can be stored in S9(8) COMP is 1,073,741,823, which is less than 999,999,999.

B. 9999999: This option is incorrect because it is less than the maximum positive value that can be stored in S9(8) COMP, which is 1,073,741,823.

C. 99999999: This option is incorrect because it is greater than the maximum positive value that can be stored in S9(8) COMP, which is 1,073,741,823.

D. 99999: This option is incorrect because it is much less than the maximum positive value that can be stored in S9(8) COMP, which is 1,073,741,823.

Therefore, the correct answer is:

The Answer is: C. 99999999

What is the maximum size of a 01 level item in COBOL II?

technology mainframe

  1. 16777215

  2. 16777200

  3. 1677250

  4. 16772150

Show answer
Correct Option: A

AI Explanation

To answer this question, you need to have an understanding of the COBOL II programming language.

In COBOL II, the maximum size of a 01 level item is determined by the PIC clause. The PIC clause defines the data type and length of the item.

The PIC X clause is used to define alphanumeric data. Each character occupies one byte of storage. Therefore, the maximum size of a 01 level item defined with PIC X is determined by the maximum number of bytes that can be allocated for a single item.

In COBOL II, the maximum number of bytes that can be allocated for a single item is 16,777,215 bytes. This corresponds to option A.

Let's go through each option to understand why they are correct or incorrect:

Option A) 16777215 - This option is correct because it represents the maximum number of bytes that can be allocated for a 01 level item in COBOL II.

Option B) 16777200 - This option is incorrect because it does not represent the maximum number of bytes that can be allocated for a 01 level item in COBOL II.

Option C) 1677250 - This option is incorrect because it does not represent the maximum number of bytes that can be allocated for a 01 level item in COBOL II.

Option D) 16772150 - This option is incorrect because it does not represent the maximum number of bytes that can be allocated for a 01 level item in COBOL II.

The correct answer is option A. This option is correct because it represents the maximum size of a 01 level item in COBOL II.

What is the output of the following code when compiled and run? Select two correct answers. public class Question01 { public static void main(String[] args){ int y=0; //line 1 int x=z=1; //line 2 System.out.println(y+","+x+","+z); //line 3 } }
technology programming languages

  1. Prints 0,1,1

  2. Error during compilation at line 1

  3. E. Error during compilation at line 2

  4. Error during compilation at line 3

Show answer
Correct Option: C,D

What is the output of the following code when compiled and run? Select one correct answer. public class Question02 { public static void main(String[] args){ int j = 017; int i = (byte)j >> 2; //line 1 System.out.println(Integer.toBinaryString(i)); //line 2 } }
technology programming languages

  1. Prints 3

  2. Error during compilation at line 1

  3. Prints 11

  4. Prints 0

Show answer
Correct Option: C

What is the output of the following code when compiled and run? Select one correct answer. import java.io.*; public class Question05 { public static void main(String[] args) { Question05Sub myref = new Question05Sub(); try{ myref.test(); }catch(IOException ioe){} } void test() throws IOException{ System.out.println("In Question05"); throw new IOException(); } } class Question05Sub extends Question05 { void test() { System.out.println("In Question05Sub"); } }

technology programming languages

  1. Prints: In Question05Sub

  2. Prints: In Question05

  3. Prints:In Question05In Question05Sub

  4. The code does not compile.

Show answer
Correct Option: D

AI Explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) Prints: In Question05Sub - This option is incorrect. Although the test() method in the Question05Sub class does not throw an exception, the test() method in the superclass Question05 throws an IOException and is called in the main() method. Since the IOException is not caught or declared in the main() method, the code does not compile.

Option B) Prints: In Question05 - This option is incorrect for the same reason as Option A. The code does not compile.

Option C) Prints: In Question05In Question05Sub - This option is incorrect for the same reason as Option A. The code does not compile.

Option D) The code does not compile - This option is correct. The code does not compile because the test() method in the superclass Question05 throws an IOException, but it is not caught or declared in the main() method.

The correct answer is D. The code does not compile because the test() method in the superclass throws an IOException, but it is not caught or declared in the main() method.

How can we create TYPE1 mappings?
technology platforms and products

  1. Using slowly changing dimension wizard

  2. Manually

  3. Both

  4. None of these

Show answer
Correct Option: C

Select three correct statements about the following code. public class Question20 { public static void main(String[] args) { Question20 myref = new Question20Sub(); try{ myref.test(); }catch(Exception e){} } void test() throws Exception{ System.out.println("In Question20"); throw new Exception(); } } class Question20Sub extends Question20 { void test() { System.out.println("In Question20Sub"); } }
technology programming languages

  1. The try-catch block that encloses myref.test(); is mandatory for the code to compile.

  2. Prints: In Question20

  3. Prints: In Question20Sub

  4. Method test() in class Question20Sub has no obligation to declare a throws clause.

  5. An exception is thrown at runtime.

Show answer
Correct Option: A,C,D

What is the output of the following code when compiled and run? Select one correct answer. public class Question41{ public static void main(String[] args){ Object[] obj = new Object[3]; for(int i=0;i
technology programming languages

  1. Compilation error.

  2. Prints: 1 3 4 true false true

  3. Prints: 1 2 4 false false true

  4. Prints: 3 4 true true true

  5. None of the above.

Show answer
Correct Option: C