What is the output of the following code when compiled and run? Select one correct answer. public class Question41{ public static void main(String[] args){ Object[] obj = new Object[3]; for(int i=0;i

obj[0]=new Object(), obj[1]=obj[-1] causes ArrayIndexOutOfBoundsException at i=1. However, re-examining: when i=1, i%2==0 is false, so obj[1]=obj[0]. Wait - obj[i-1] when i=1 is obj[0], which exists. So array fills: obj[0]=new Object(), obj[1]=obj[0](same reference), obj[2]=obj[1](same reference). All three entries point to one object. First if: obj[0]obj[1] is true, assignment obj[1]=obj[2] is redundant but not null, prints '1'. Second if: obj[1]obj[2] is true, obj[2]=obj[0] redundant, but && requires both sides - first part true so evaluation continues, prints '2'. Third if: obj[1]obj[0] is true (short-circuit ||), skips assignment, prints '3'. Fourth if: | is non-short-circuit, so assignment executes but obj[0]obj[2] always true, prints '4'. Final comparison: all three are same reference, so 'false false true'. Wait, re-tracing second if: after first if, obj[1]=obj[2](same obj). obj[1]obj[2] is true. && evaluates left to right, both conditions true. But re-reading the && logic more carefully - when obj[1]obj[2] is true, it proceeds to check (obj[2]=obj[0])!=null. That's true. So '2' prints. Option C shows '1 2 4' - let me verify again. Actually looking at the answer C: '1 2 4 false false true'. The obj comparisons at end: obj[0]==obj[1] after all the shuffle... hmm.