What is the output of the following code when compiled and run? Select one correct answer. import java.io.*; public class Question05 { public static void main(String[] args) { Question05Sub myref = new Question05Sub(); try{ myref.test(); }catch(IOException ioe){} } void test() throws IOException{ System.out.println("In Question05"); throw new IOException(); } } class Question05Sub extends Question05 { void test() { System.out.println("In Question05Sub"); } }

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  1. Prints: In Question05Sub

  2. Prints: In Question05

  3. Prints:In Question05In Question05Sub

  4. The code does not compile.

Show answer
Correct Option: D

AI Explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) Prints: In Question05Sub - This option is incorrect. Although the test() method in the Question05Sub class does not throw an exception, the test() method in the superclass Question05 throws an IOException and is called in the main() method. Since the IOException is not caught or declared in the main() method, the code does not compile.

Option B) Prints: In Question05 - This option is incorrect for the same reason as Option A. The code does not compile.

Option C) Prints: In Question05In Question05Sub - This option is incorrect for the same reason as Option A. The code does not compile.

Option D) The code does not compile - This option is correct. The code does not compile because the test() method in the superclass Question05 throws an IOException, but it is not caught or declared in the main() method.

The correct answer is D. The code does not compile because the test() method in the superclass throws an IOException, but it is not caught or declared in the main() method.

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