Tag: nuclear structure

Questions Related to nuclear structure

Inside nucleus, protons are held together though they have the dame charge. Why?

  1. The strong attractive nuclear force far exceeds the electrostatic force between the protons

  2. Neutrons prevent them from repelling from each other

  3. The electrostatic attractive force between an electron and a proton is more than the electrostatic repulsive force between the protons

  4. Gluons are responsible for holding them together


Correct Option: A

The conversion of 1 u of mass results in ________ eV of energy.

  1. $9.315 \times 10^6$

  2. $391.5 \times 10^6$

  3. $931.5 \times 10^6$

  4. $93.15 \times 10^6$


Correct Option: C

Magnitude of mass defect is a measure of ......................... of a nucleus.

  1. Unstability

  2. Stability

  3. Charge

  4. Position


Correct Option: B

What is energy equivalent to a $10\ \mu g$ mass?

  1. $9\ \times 10^{7}\ J$

  2. $3\ \times 10^{11}\ J$

  3. $5\ \times 10^{11}\ J$

  4. $7\ \times 10^{11}\ J$


Correct Option: A

A proton and an -particle enters a uniform magnetic field moving with the same speed. If the proton Takes 25s to make 5 revolutions, what is the periodic time for the -particle?

  1. 50 s

  2. 25 s

  3. 10 s

  4. 5 s


Correct Option: D

In a laboratory experiment on emission from atomic hydrogen in a discharge tube, only a small number of lines are observed where as a lines are present in the hydrogen spectrum of a star. This is because in a laboratory  

  1. The amount of hydrogen taken is much smaller than that present in the star

  2. The temperature of hydrogen is much smaller than that of the star

  3. The pressure of hydrogen is much smaller than that of the star

  4. The gravitational pull is much larger than that in the star


Correct Option: C

Ionization energy of $Li$(Lithium) atom in ground state in $5.4 eV$. Binding energy of an electron in $Li^+$ ion in ground state is $75.6 eV$. Energy required to remove all three electrons of Lithium (Li) atom is:-

  1. $203.4 \ eV$

  2. $135.4 \ eV$

  3. $81.0 \ eV$

  4. $156.6 \ eV$


Correct Option: D

In a hypothetical star,two carbon nuclei fuse to form magnesium.The reaction is:(take :$1amu=931MeV/c^2)$
$^{12}C+^{12}C\rightarrow ^{24}Mg$
The energy released per carbon nuclei is: (Mass of $^{24}Mg=23.985amu)$

  1. $13.965 MeV$

  2. $11.12 MeV$

  3. $6.982 MeV$

  4. $10.12 MeV$


Correct Option: A
Explanation:

$^{12}C+^{12}C\rightarrow ^{24}Mg$
mass of $^{12}C=12.0642 amu$
Total input mass $m _1=2\times 12.0642$
$=24.1284$ amu
Mass of $^{24}Mg$=output mass
$=m _0=23.955$
mass loss $=m _1-m _o$
$Am=24.1284-23.985$
$=0.1434 amu$
Energy released $=0.1434\times 931 Mev$
$=13.965 Mev$

One milligram of matter converted into energy will give

  1. $9$ J

  2. $9 \times 10^{13}$ J

  3. $9 \times 10^5 $ J

  4. $9 \times ^{10}$ J


Correct Option: D

One mole of radium has an activity of 1/3.7 killo curie. Its decay constant will be 

  1. $\frac{1}{6}\times -10s^{-1}$

  2. $ 10^{-10}s^{-1}$

  3. $ 10^{-11}s^{-1}$

  4. $ 10^{-8}s^{-1}$


Correct Option: C
Explanation:

Number of mole of radium, $n=1$

The number of nuclei of radium, $N={{N} _{a}}=avagdaro\,\,number=6.023\times {{10}^{23}}$

Activity, $A=\lambda N$

$ \because 1\,\,curie=3.7\times {{10}^{10}}\,decay/\sec  $

$ \dfrac{1}{3.7}\,kilocurie=0.27\,kilocurie=9.99\times {{10}^{12}}\,dacay/\sec  $

So, $\lambda =\dfrac{A}{N}=\dfrac{9.99\times {{10}^{12}}}{6.023\times {{10}^{23}}}=1.65\times {{10}^{-11}}\,$