Tag: oxoacids of halogens

Questions Related to oxoacids of halogens

Which of the following is used to prepare $Cl _{2}$ gas at room temperature from concentrated $HCl$?

  1. $MnO _{2}$

  2. $H _{2}S$

  3. $KMnO _{4}$

  4. $Cr _{2}O _{3}$


Correct Option: A,C
Explanation:

Manganese dioxide($MnO _2$) is heated with concentrated $HCl$ to form $Cl _2$

$MnO _2+4HCl\rightarrow MnCl _2+Cl _2+2H _2O$

 $HCl$ in action with potassium permanganate gives $C _2$

$2KMnO _4+16HCl\rightarrow 2KCl+2MnCl _2+8H _2O+5Cl _2$.

Hence option A and C is correct.

Which of the following statements is not correct?

  1. All the oxides of halogens are powerful oxidants.

  2. The compounds of oxygen and fluorine are not called oxides but fluorides.

  3. Oxygen fluorides form oxoacids.

  4. In oxyhalides, bonds are mainly covalent due to small difference in electronegativity of oxygen and halogens.


Correct Option: C
Explanation:

Oxygen florides forms $HF,O _2$ on hydrolysis.

$OF _2 + H _2O\rightarrow O _2 + 2 HF$

$2O _2F _2 + 2H2O\rightarrow O _2 + 4HF$

so oxygen florides do not form forms hypohalous acids.

So the given statement oxygen florides forms oxoacids is wrong.

Hence option C is correct.

Bleaching powder and bleach solution are produced on a large scale and is used in several house-hold products. The effectiveness of bleach solution is often measured by iodometry. Bleaching powder contains a salt of an oxoacid as one of its components. The anhydride of that oxoacid is:

  1. $Cl _{2}O$

  2. $Cl _{2}O _{7}$

  3. $ClO _{2}$

  4. $Cl _{2}O _{6}$

  5. $Cl _2O _3$

  6. $Cl _2O _5$

  7. $Cl _3O _9$

  8. $Cl _3O _5$


Correct Option: A
Explanation:

Bleaching powder is $Ca(OCl)Cl$.


So, bleaching powder contains a salt of $HOCl$.

$Cl _2O$ is an anhydride of $HOCl$.

$Cl _2O+H _2O\Rightarrow 2HOCl$.

Hence, option A is correct.

Hypo chlorite radical is represented as $(HClO _2)^{-1}$.

  1. True

  2. False


Correct Option: B
Explanation:

Hypochlorite radical is represented as $ClO^-$. Thus the given statement is false.

$10 ml$ of chlorine gas and $25 ml$ of Oxygen gas reacts to form?

  1. $Cl _{2}O$

  2. $Cl _{2}O _{7}$

  3. $ClO _{2}$

  4. $Cl _{2}O _{5}$


Correct Option: D

The oxidation state of chlorine in chlorous acid is:

    • 2
    • 3
    • 1
    • 2

Correct Option: B
Explanation:

Chlorous acid = $\overset{+1\ +3\ -4}{HClO _{2}}$
Let oxidation state of chlorine be x.
$\therefore{x}+1+2(-2)=0$
Here oxidation state of oxygen is -2 and that of hydrogen is +1.
$\therefore x=+3$
oxidation state in chlorous acid of chlorine is +3.

The oxidation number of chlorine in KClO is:

    • 1
    • 3
    • 5
    • 7

Correct Option: A
Explanation:

$\overset{+1}{K}Cl\overset{-2}{O}$
oxidation state of alrali metals = +1
oxygen = -2

Let oxidation state of chlorine is x.
$\therefore$ x+1+(-2) = 0
$\therefore$ x = +1 
Thus, oxidation state of chlorine in potassium chlorate is +1.

Chemically bleaching powder is called:

  1. Calcium oxychloride

  2. Calcium chlorohypochlorite

  3. Calcium monooxygen chloride

  4. Calcium oxygen dichloride


Correct Option: B
Explanation:


Bleaching powder is also called calcium chlorohypochlorite because it is considered as a mixed salt of hydrochloric acid and hypochlorous acid. 


Option B is correct.

The oxidation state of Chlorine in Bleaching Powder:

  1. -2

    • 1
    • 1
  2. -1 and + 1


Correct Option: D
Explanation:

The chemical formula of bleaching powder is $CaOCl _{2}$. Here, calcium is bonded to $Cl^{-}$ ion and $OCl^{-}$ ion respectively.

In $Cl^{-}$ the oxidation state of chlorine is -1 and in $OCl^{-}$ ion the oxidation state of chlorine is +1.

The chemical formula of the oxyacid of chlorine in which chlorine exhibits its highest oxidation state is:

  1. $HOCl$

  2. $HClO _2$

  3. $HClO _3$

  4. $HClO _4$


Correct Option: D
Explanation:

$HCIO _4$ has highest oxidation state of chlorine i.e + 7