Tag: oxoacids of halogens

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Multiple choice oxoacids of halogens p- block elements-ii p-block elements the p-block elements chemistry

The increasing order of the acidity of the following acids is:


 l) $H _{2}SO _{3}$
ll) $H _{3}PO _{3}$ 
lll) HClO$ _{3}$

  1. l>lll>ll

  2. l > ll > lll

  3. lll>l >lI

  4. ll>lll>l
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
Here as the non-metallic nature of the central atom increases, its acidity increases in its oxyacids Thus, increasing order of acidity will be:
III > I >II
Multiple choice oxoacids of halogens p- block elements-ii p-block elements the p-block elements chemistry

Match the following


Set-l (Cl-O bond length)       Set -ll($\mathrm{A}^{0})$
$\mathrm{A}) H\mathrm{C}lO$                                 1)$ 1.64$
$\mathrm{B}) HClO _{2}$                               2$) 1.70$
$\mathrm{C}) HClO _{3}$                               3$)$ 1.45
$\mathrm{D}) HClO _{4}$                               4$) 1.57$

The correct matching is:

  1. A-1, B-2, C-3, D-4

  2. A-2, B-3, C-4, D-1

  3. A-2, B-1, C-4, D-3

  4. A-2, B-1, C-3, D-4
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Bond order $\propto \ \frac{1}{Bond\ length}$


Bond order of $HClO _4 > HClO _3 > HClO _2> HClO$

Bond length
$HClO > HClO _2 > HClO _3 > HClO _4$

Multiple choice oxoacids of halogens p- block elements-ii p-block elements the p-block elements chemistry

Number of valence electrons present in atoms of $HClO _{4},HClO _{3},HClO _{2}$ respectively are :

  1. $32,26,20$
  2. $26,20,14$
  3. $36,30,24$
  4. $28,22,16$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Number of valence electrons present in atoms of $HClO _{4},HClO _{3},HClO _{2}$ are32,26,20 respectively.
Number of valence electrons present in atoms of  $HClO _{4}$ are $1+7+4(6)=32$
Number of valence electrons present in atoms of  $HClO _{3}$ are $1+7+3(6)=26$
Number of valence electrons present in atoms of  $HClO _{2}$ are $1+7+2(6)=20$

Multiple choice oxoacids of halogens p- block elements-ii p-block elements the p-block elements chemistry

Which selection is the correct formula for the chlorate ion?

  1. ${Cl}^{-}$
  2. $Cl{O}^{-}$
  3. $Cl{O} _{2}^{-}$
  4. $Cl{O} _{3}^{-}$
  5. $Cl{O} _{4}^{-}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The correct formula for the chlorate ion is $Cl{O} _{3}^{-}$
The formula $Cl{O}^{-}$ represents hypochlorite ion.
The formula $Cl{O} _{2}^{-}$ represents chlorite ion.
The formula $Cl{O} _{4}^{-}$ represents perchlorate ion.

Multiple choice oxoacids of halogens p- block elements-ii p-block elements the p-block elements chemistry

$NaOCl$ is used as a bleaching agent and sterilising agent. It can be prepared by the action of:

  1. $NaCl$ with $H _2O$
  2. $NH _4Cl$ with $NaOH$
  3. $Cl _2$ with cold and dil. $NaOH$
  4. $Cl _2$ with hot and conc. $NaOH$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
Chlorine with cold and dilute sodium hydroxide give mixture of chloride salt, hypochlorite and water.

$Cl _2 (l) + 2NaOH (aq) \rightarrow NaCl+ NaClO (aq) + H _2O(l) $

Chlorine with hot and dilute sodium hydroxide give mixture of chloride salt, hypochlorite and water.

$3 Cl _2 (l) + 6 NaOH (aq) \rightarrow 5 NaCl + NaClO _3 (aq) + 3 H _2O (l) $

Hence, the correct option is $C$
Multiple choice oxoacids of halogens p- block elements-ii p-block elements the p-block elements chemistry

Which of the following does exist?

  1. $HFO _2$
  2. $HClO _2$
  3. $HBrO _2$
  4. $HIO _2$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation
$HClO _2$ is a chlorous acid which is oxyacid of halogen.
Remaining oxyacids of halogens do not exist.

Bromous acid $HBrO _2$ and Iodous acid $HIO _2$  and fluorous acid are not likely to exist in nature as they would decompose into oxides and water vapour when trying to isolate them from their respective acid solutions.

Hence, option $B$ is correct.

Multiple choice oxoacids of halogens p- block elements-ii p-block elements the p-block elements chemistry

${ COCl } _{ 2 }$ gas dissociates according to the equation
${ COCl } _{ 2 }(g)\ \rightleftharpoons \ CO(g)\ +\ { Cl } _{ 2 }(g)$
When ${ COCl } _{ 2 }$ is heated to 700 K at 100 kPa, density of the gas mixture at equilibrium is $1.2\ { gdm }^{ -3 }$. The percentage degree of dissociation of ${ COCl } _{ 2 }$ is: 

$(R = 8.314\ kPa\ { dm }^{ 3 } { K }^{ -1 }\ { mol }^{ -1 })$

  1. 41

  2. 81

  3. 60

  4. 20
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Using the ideal gas law PV=nRT and the relationship between density, molar mass, and degree of dissociation (alpha), one can solve for alpha. Given the density 1.2 g/dm3 at 700K and 100 kPa, the calculation yields approximately 41%.