Tag: time period, frequency and amplitude of sound

Questions Related to time period, frequency and amplitude of sound

Which type of wave can be diffused by Acoustic diffusers?

  1. sound waves

  2. light waves

  3. water waves

  4. microwaves

  5. ultraviolet rays


Correct Option: A
Explanation:

Sound waves can be diffused by Acoustic diffusers but not the other given waves. 

Sound waves can diffract easily because

  1. Their wavelength is very small

  2. Their wavelength is large

  3. It can reflect

  4. It can refract


Correct Option: B
Explanation:

Having a very large wavelength made the waves to bend more, when they meet on obstacle.

Time taken to complete a wave is called as

  1. Period 

  2. Span

  3. Life 

  4. Duration 


Correct Option: A
Explanation:

The time taken to complete a wave is termed as period which can be written as $T=\dfrac{1}{f}$ T= time period ; f= frequency 

The wavelength of light absorbed by $Pr$ form of phytochrome is:-

  1. $620 nm$

  2. $640 nm$

  3. $680 nm$

  4. $720 nm$


Correct Option: C
Explanation:

The Pr form absorbs light between $660$ to $680 nm$ and absorbs at a peak of $666 nm$. It is the form synthesized in dark-grown seedlings. When Pr absorbs red light, it is converted to the $Pfr$ form.

Which of the following type of waves is different from others? 

  1. Light waves

  2. X-rays

  3. Radio waves

  4. Sound waves


Correct Option: D
Explanation:

Except sound wave, all other options are electromagnetic waves.

The frequency of a man's voice is $300Hz$ and its wavelength is $1$ meter. If the wavelength of a child's voice is $1.5m$, then the frequency of the child's voice is:

  1. $200Hz$

  2. $150Hz$

  3. $400Hz$

  4. $350Hz$


Correct Option: A
Explanation:

We know that ,

$f=\dfrac{c}{\lambda}$
So,
$\dfrac{f _{man's voice}}{f _{child's voice}}=\dfrac{\dfrac{c}{\lambda _{man's voice}}}{\dfrac{c}{\lambda _{child's voice}}}$
$\dfrac{f _{man's voice}}{f _{child's voice}}$=$\dfrac{\lambda _{child's voice}}{\lambda _{man's voice}}$     
$\dfrac{300}{f _{child's voice}}=\dfrac{1.5}{1}$
$f _{child's voice}=\dfrac{300}{1.5}$
$f _{child's voice}=200 Hz$
  

two waves of same frequency and of intensity ${I} _{0}$ and $9{I} _{0}$ produces interference. If at a certain point the resultant intensity is $7{I} _{0}$ then the minimum phase difference between the two sound waves will be

  1. ${90}^{0}$

  2. ${150}^{0}$

  3. ${120}^{0}$

  4. ${100}^{0}$


Correct Option: C
Explanation:

$\begin{array}{l} 7{ I _{ o } }={ I _{ o } }+a{ I _{ o } }+2\sqrt { { I _{ o } } } \sqrt { x{ I _{ o } } } \cos  \Delta \phi  \ \Rightarrow 7{ I _{ o } }=10{ I _{ o } }+6\cos  \Delta \phi  \ \Rightarrow -3{ I _{ o } }=6\cos  \Delta \phi  \ \cos  \Delta \phi ={ { -1 } }{ 2 } \ \Delta \phi =\dfrac { { 2\pi  } }{ 3 } =\dfrac { { 2\times 180 } }{ 3 } ={ 120^{ 0 } } \ Hence, \ option\, \, C\, \, is\, \, correct\, \, answer. \end{array}$

Sound frequency that can be detected by the human ear is 

  1. $1500\ Hz$

  2. $20,000\ Hz$

  3. $12,000\ Hz$

  4. $22,000\ Hz$


Correct Option: B

When you speak to your friend which of the following quantities have a unique value in the sound produced by both the boys?

  1. amplitude

  2. wave velocity

  3. frequency

  4. wavelength


Correct Option: B
Explanation:

Out of the given quantities , wave velocity has a unique value . Because both the friends are producing the sound in the same medium , and wave velocity depends upon medium , which is not changing here .

Amplitude of the sounds depends upon the energy given by any of the friends to sound , so it may change .
Frequency of sound depends upon the thickness of vocal cords of two friends , so it also may vary . Now wavelength $\lambda \propto 1/f$, for a constant velocity , when frequency $f$ changes , wavelength will also change .

What is the unit of frequency?

  1. Hz

  2. Watt

  3. Volt

  4. $m^{-1}$


Correct Option: A
Explanation:

The unit of frequency is Hz.