Tag: real numbers

Absolute value of a number is its numerical value without any sign.

Absolute value of $x$ is given by
$|x|=x, x\ge0 \text{ or} -x, x<0 $
Since $131>0$
$\therefore |131|=131$
Option $D$ is correct.

$|x|=x$  when  $x>0$
$|x|=-x$  when  $x<0$
That means it always gives positive quantity.
Now,
$|3-10|=|-7|=7$

The absolute value of $0$ is $|0|=0.$

$-3 \times 6 = -18$
Absolute value of a number means the distance of a number 
on the number line from $0$, without considering which 
direction from $0$ the number lies.
$\therefore$ absolute value i.e $|-18|= 18$.

$| 10 \div (-2)|$ = $|-5|$
The absolute value i.e $|-5| = 5$.

$ | -8 + 3| = | -5 | $
$\therefore$ absolute value i.e $|-5| = 5$.

$ | 8 - 3| = | 5 | $
$\therefore$ absolute value i.e $|5| = 5$.
Therefore, option $A$ is correct.