Tag: perimeter and area of rectilinear figures

Questions Related to perimeter and area of rectilinear figures

Multiple choice maths perimeter and area of rectilinear figures parallelogram and rectangle area of parallelogram area of a parallelogram

A parallelogram has sides $30m$ and $14m$ and one of its diagonals is $40m$ long. Then, its area is:

  1. $168{m}^{2}$
  2. $336{m}^{2}$
  3. $372{m}^{2}$
  4. $480{m}^{2}$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
Area of parallalogram = $2\times area of triangle $
Area of triangle where three sides a,b,c are given is $\sqrt{s(s-a)(s-b)(s-c)}$, where $s=\dfrac{a+b+c}{2}$
Here $s=\dfrac{30+14+40}{2}=42$
$Area\ of \triangle=\sqrt{(42)(12)(28)(2)}=\sqrt{28224}=168m^2$
Therefore area of parallalogram = $336 m^2$
Hence option B is correct
Multiple choice maths perimeter and area of rectilinear figures parallelogram and rectangle area of parallelogram area of a parallelogram

Point $A(2,1),B(3,-7),C$ is any point on the line $3x-2y=1$, then locus of point $D$ such that$ABCD$ is a parallelogram

  1. $3x-2y=20$
  2. $3x-y=20$
  3. $2x+3y=20$
  4. $3x-2y+18=0$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

In a parallelogram ABCD, the diagonals bisect each other. The midpoint of AC must equal the midpoint of BD. Using this property with C on the line 3x-2y=1, we derive the locus of D.

Multiple choice maths perimeter and area of rectilinear figures parallelogram and rectangle area of parallelogram area of a parallelogram

The area four walls of a hall is $320\ m^{2}$. The length & breadth of the hall is $12.5\ m$ & $7.5\ m$ respectively, Find the height of the hall.

  1. $32\ m$
  2. $9\ m$
  3. $3\ m$
  4. $5\ m$
  5. $None\ of\ these$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
formula,

$\dfrac{(l+b)h}{2}=area$

$\dfrac{(12.5+7.5)h}{2}=320$

$(12.5+7.5)h=640$

$20h=640$

$\therefore h=32m$

Multiple choice maths perimeter and area of rectilinear figures parallelogram and rectangle area of parallelogram area of a parallelogram

if $\hat { i } +2\hat { j } +3\hat { k } $ and $ 3\hat { i } -2\hat { j } +\hat { k } $ are the adjacent sides of a parallelogram, then its area will be 

  1. $8\sqrt { 3 } $
  2. $5\sqrt { 3 } $
  3. $16\sqrt { 3 } $
  4. $6\sqrt { 3 } $
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

We have,

$ \overrightarrow{a}=\widehat{i}+2\widehat{j}+3\widehat{k} $

$ \overrightarrow{b}=3\widehat{i}-2\widehat{j}+\widehat{k} $


We know that,

Area of parallelogram $=\left| \begin{matrix} i & j & k \\ 1 & 2 & 3 \\ 3 & -2 & 1 \end{matrix} \right| $

$ =\left( -6-2 \right)\widehat{i}-\widehat{j}\left( 9-1 \right)+\widehat{k}\left( 6+2 \right) $

$ =-8\widehat{i}-8\widehat{j}+8\widehat{k} $


$ Now, $

$ \left| \overrightarrow{a}\times \overrightarrow{b} \right|=\sqrt{{{\left( -8 \right)}^{2}}+{{\left( -8 \right)}^{2}}+{{8}^{2}}} $

$ =\sqrt{64+64+64} $

$ =\sqrt{3\times 64} $

$ =8\sqrt{3}\,\,sq.\,unit $


Hence, this is the answer.

Multiple choice maths perimeter and area of rectilinear figures parallelogram and rectangle area of parallelogram area of a parallelogram

ABCD is a parallelogram with sides $AB = 12\ cm$, $BC = 10\ cm$ and diagonal $AC = 16\ cm$. Find the approximate area of the parallelogram.

  1. $119.8cm^2$
  2. $103.7cm^2$
  3. $15.7cm^2$
  4. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
Area of triangle with sides $12\ cm, 10\ cm, 16\ cm$:
$s=\dfrac{12+10+16}{2}=19$

Area, A = $\sqrt{s(s-a)(s-b)(s-c)}$

$A=\sqrt{19(19-12)(19-10)(19-16)}$

$A=59.9$ sq. cm

Therefore,
Area of parallelogram $=2A = 2\times 59.9 = 119.8$ sq. cm
Multiple choice maths perimeter and area of rectilinear figures parallelogram and rectangle area of parallelogram area of a parallelogram

Which of the following statements are true (T) and which are false (F)?
If three angles of a quadrilateral are equal, it is a parallelogram.

  1. True

  2. False

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

A quadrilateral with three equal angles is not necessarily a parallelogram. For example, a kite can have three equal angles but is not a parallelogram.

Multiple choice maths perimeter and area of rectilinear figures parallelogram and rectangle area of parallelogram area of a parallelogram

Which of the following statements are true (T) and which are false (F)?
If three sides of a quadrilateral are equal, it is a parallelogram.

  1. True

  2. False

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$\Rightarrow$  We know that, in parallelogram opposite sides are parallel and equal in length.

$\Rightarrow$  In some case all four sides are equal in length. ( Square and rhombus )
$\Rightarrow$  But we can't say that, three sides are equal than that is a parallelogram. That doesn't satisfied the properties of a parallelogram.
$\therefore$  If three sides of a quadrilateral are equal then it is not a parallelogram.
$\therefore$  The given statement is false.
 

Multiple choice maths perimeter and area of rectilinear figures parallelogram and rectangle area of parallelogram area of a parallelogram

Two opposite angles of a parallelogram are $(3x-2)^{\circ}$ and $(50-x)^{\circ}$. Find the measure of each angle of the parallelogram.

  1. $40^{\circ},140^{\circ},40^{\circ},140^{\circ}$
  2. $37^{\circ},143^{\circ},37^{\circ},143^{\circ}$
  3. $35^{\circ},145^{\circ},35^{\circ},145^{\circ}$
  4. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Since opposite angles of a parallelogram are equal. Therefore,
$3x-2=50-x\Rightarrow x=13$


$(3x−2)^{\circ}=3(13)-2=37^{\circ}$

The measures of the adjacent angles of a parallelogram add up to be $180$ degrees, or they are supplementary.
Another angle $=180-37=143^{\circ}$

The measure of each angle of the parallelogram.
$37^{\circ},143^{\circ},37^{\circ},143^{\circ}$

Multiple choice maths perimeter and area of rectilinear figures parallelogram and rectangle area of parallelogram area of a parallelogram

Find the measure of all the angles of a parallelogram, if one angle is $24^{\circ}$ less than twice the smallest angle.

  1. $68^{\circ},112^{\circ},68^{\circ},112^{\circ}$
  2. $48^{\circ},72^{\circ},48^{\circ},72^{\circ}$
  3. Insufficient data

  4. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the smallest angle be of $x^{\circ}$. 


Then, the other angle is of $(2x-24)^{\circ}$. 

Since adjacent angles of a parallelogram are supplementary.

$\therefore x^{\circ}+(2x-24)^{\circ}=180^{\circ}\Rightarrow x=68^{\circ}$


$(2x-24)^{\circ}=2(68)-24=112^{\circ}$


The measure of all the angles of a parallelogram are
$68^{\circ},112^{\circ},68^{\circ},112^{\circ}$