Tag: perimeter and area of rectilinear figures

Questions Related to perimeter and area of rectilinear figures

Multiple choice maths perimeter and area of rectilinear figures region enclosed by a plane figure area of square and rectangle mensuration-i (area)

The perimeter of a rhombus is 100 cm and one of the diagonals is 40 cm, Then the area of the rhombus is

  1. 1000 cm$^2$
  2. 500 cm$^2$
  3. 1200 cm$^2$
  4. 600 cm$^2$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Given that, perimeter of rhombus is $100cm$ and one diagonal $40cm$

Perimeter of rhombus=4$\times $side

So side$=25cm$

And we know that in a rhombus diagonal divides rhombus in two eauilateral triangle.

Area of one triangle:- s$=(25+25+40)/2 =45$

So area=(s$\times $(s-a)$\times $ (s-b)$\times $(s-c))^1/2

= (45$\times $(45-40)$\times $(45-25)$\times $(45-25))^1/2

$= 300cm^2$

So total area is 300$\times $2=600cm^2

 

Hence, this is the answer.

Multiple choice maths perimeter and area of rectilinear figures unit of area units of area units of area and volume converting between units of areas the metric system metric system

By converting the $4.8mm^{2}$ into the $m^2,$ the answer will be

  1. $4.8 \times 10^{-7} m^2$
  2. $4.8 \times 10^{-6} m^2$
  3. $4.8 \times 10^{-8} m^2 $
  4. $4.8 \times 10^{-5}m^2$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

1 mm = 10^-3 m, so 1 mm^2 = (10^-3)^2 m^2 = 10^-6 m^2. 4.8 mm^2 = 4.8 * 10^-6 m^2.