Tag: properties of acids and bases

Questions Related to properties of acids and bases

Colourless solution of silver nitrate is taken in two test tubes A and B. Metal plates of copper and platinum are dipped into test tubes, A and B respectively. Content of test tubes ____________.

  1. B turns green

  2. B turns blue

  3. A turns blue

  4. A remains colourless


Correct Option: C
Explanation:

In test tube A, displacement reaction takes place as copper being more reactive displaces silver from silver nitrate solution thus leading to the formation of copper nitrate which is blue in colour. The chemical reaction can be written as:
$Cu + Ag(NO _{3}) _{2} \rightarrow Cu(NO _{3}) _{2} + Ag$

When sodium iodide is heated with concentrate sulphuric acid,the vapour evolved is-

  1. Iodine

  2. ${SO} _{2}$

  3. Sulphuric acid

  4. Oxygen


Correct Option: A
Explanation:

$2NaI+{ H } _{ 2 }{ SO } _{ 4 }\xrightarrow [  ]{ heated } { Na } _{ 2 }{ SO } _{ 4 }+2HI$
$2HI\xrightarrow [  ]{ heated }  {H} _{2}+{I} _{2}$

Which of the following equation is not correct?

  1. Amphoteric oxide / Hydroxide + Acid$\rightarrow$ Salt + Water

  2. Amphoteric oxide / Hydroxide + Alkali$\rightarrow$ Salt + Water

  3. Metal + Alkali$\rightarrow$ Salt + Water

  4. Metal + Alkali$\rightarrow$ Salt + Hydrogen


Correct Option: C

Which of the following equation represents action of alkali on oxide?

  1. $ZnO+2NaOH\rightarrow Na _2ZnO _2+H _2O$

  2. $Zn\begin{pmatrix}OH\end{pmatrix} _2+2NaOH\rightarrow NaZnO _2+2H _2O$

  3. $PbO+2NaOH\rightarrow Na _2PbO _2+2H _2O$

  4. Both A and C


Correct Option: A
Explanation:

Oxides of certain metals react with acid and alkali to give salt and water.
$ZnO+2NaOH\rightarrow Na _2ZnO _2+H _2O$ is the only correct equation.

Which of the following equation represents action of alkali on hydroxide?

  1. $ZnO+2NaOH\rightarrow Na _2ZnO _2+H _2O$

  2. $Zn\begin{pmatrix}OH\end{pmatrix} _2+2NaOH\rightarrow Na _2ZnO _2+2H _2O$

  3. $PbO+2NaOH\rightarrow Na _2PbO _2+2H _2O$

  4. Both A and C


Correct Option: B
Explanation:

$Zn\begin{pmatrix}OH\end{pmatrix} _2+2NaOH\rightarrow Na _2ZnO _2+2H _2O$ represents action of alkali on hydroxide.

Complete the following equation
$PbO+NaOH\rightarrow$

  1. $PbO+2NaOH\rightarrow Na _2PbO _2+H _2O$

  2. $PbO+NaOH\rightarrow2Na _2PbO _2+H _2O$

  3. $PbO+2NaOH\rightarrow2Na _2PbO _2+H _2O$

  4. $PbO+NaOH\rightarrow Na _2PbO _2+H _2O$


Correct Option: A
Explanation:

$PbO+2NaOH\rightarrow Na _2PbO _2+H _2O$ 

Which of the following equation represents action of alkali on aluminium hydroxide?

  1. $Al\begin{pmatrix}OH\end{pmatrix} _3+NaOH\rightarrow NaAlO _2+2H _2O$

  2. $Al\begin{pmatrix}OH\end{pmatrix} _3+2KOH\rightarrow2KAlO _2+H _2O$

  3. $Al\begin{pmatrix}OH\end{pmatrix} _3+KOH\rightarrow KAlO _2+2H _2O$

  4. Both A and C


Correct Option: D

Chromium hydroxide on reaction with excess $\displaystyle NaOH$ gives a soluble compound. Guess the colour of the compound :

  1. Dark green

  2. Dark blue

  3. Purple

  4. Pink


Correct Option: A
Explanation:

Chromium hydroxide provide dark green solution with excess of NaOH.

Complete the following equation
$Pb\begin{pmatrix}OH\end{pmatrix} _2+NaOH\rightarrow$

  1. $Pb\begin{pmatrix}OH\end{pmatrix} _2+2NaOH\rightarrow Na _2PbO _2+2H _2O$

  2. $Pb\begin{pmatrix}OH\end{pmatrix} _2+NaOH\rightarrow2Na _2PbO _2+H _2O$

  3. $Pb\begin{pmatrix}OH\end{pmatrix} _2+2NaOH\rightarrow Na _2PbO _2+H _2O$

  4. $Pb\begin{pmatrix}OH\end{pmatrix} _2+NaOH\rightarrow Na _2PbO _2+2H _2O$


Correct Option: A
Explanation:

$Pb\begin{pmatrix}OH\end{pmatrix} _2+2NaOH\rightarrow Na _2PbO _2+2H _2O$

Chromium hydroxide on reaction with excess $\displaystyle NaOH$ gives a soluble compound. Guess the molecular formula.

  1. $\displaystyle \left[ { Cr\left( OH \right) } _{ 3 } \right] $

  2. $\displaystyle { \left[ { Cr\left( OH \right) } _{ 4 } \right] }^{ - }$

  3. $\displaystyle { \left[ { Cr\left( OH \right) } _{ 5 } \right] }^{ 2- }$

  4. $\displaystyle { \left[ { Cr\left( OH \right) } _{ 6 } \right] }^{ 3- }$


Correct Option: D
Explanation:

An excess of sodium hydroxide solution is added to a solution of the hexaaquachromium(III) ions to produce a solution of green hexahydroxochromate(III) ions.

$[Cr(H _2O) _6]^{3+} \xrightarrow{NaOH} [Cr(H _2O) _3(OH) _3] \xrightarrow{excess NaOH} [Cr(OH) _6]^{-3}$