Tag: properties of acids and bases

Questions Related to properties of acids and bases

Which of the following is least basic?

  1. NF3N

  2. NH3

  3. NCl3

  4. NI3


Correct Option: A

In which case of mixing a strong acid and a base each of $1$N concentration, temperature rise is highest?

  1. $20$ ml, acid + $30$ ml alkali

  2. $10$ ml, acid + $40$ ml alkali

  3. $20$ ml, acid + $20$ ml alkali

  4. $30$ ml, acid + $20$ ml alkali


Correct Option: C
Explanation:

More amount of acid reacts with equal amount of base, higher the amount of heat releases.

So, $20ml$ of acid+$20ml$ of alkali.

Conjugate base of ${ H } _{ 3 }{ PO } _{ 4 }$?

  1. ${ H } _{ 2 }{ PO } _{ 4 }^{ - }$

  2. ${ H } _{ }{ PO } _{ 4 }^{ 2- }$

  3. ${ H } _{ 4 }{ PO } _{ 4 }^{ + }$

  4. ${ H } _{ 3 }{ PO } _{ 4 }^{ }$


Correct Option: A
Explanation:

${H _2PO _4}^-$ is conjugate base of $H _3PO _4$  .

$H _2O _2$ is a:

  1. monobasic acid

  2. dibasic acid

  3. neutral compound

  4. weal alkali


Correct Option: B
Explanation:
A dibasic molecule has two replaceable hydrogen atoms. Since $H _2O _2$ has two replaceable hydrogen atoms, That's why it is a dibasic acid.

$H _2O _2\rightarrow HO _2^−+H^+$

$HO _2^−\rightarrow O _2^{−2}+H^+$


$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (B)}$

Which of the following equation is the correct one?

  1. Amphoteric oxide / Hydroxide + acid$\rightarrow$ Salt + Hydrogen

  2. Amphoteric oxide / Hydroxide + alkali$\rightarrow$ Salt + Hydrogen

  3. Metal + alkali$\rightarrow$ Salt + Water

  4. Metal + alkali$\rightarrow$ Salt + Hydrogen


Correct Option: D
Explanation:

Amphoteric oxide reacts with acid/alkali to produce salt and water not salt and hydrogen. Also, Metal and alkali react to give salt and liberate hydrogen not water. So, option D is correct.

Find the odd one with reasons [valency is not a criterion]: $Al(OH) _3, Pb(OH) _2, Mg(OH) _2, Zn(OH) _2$ :

  1. $Al(OH) _3$

  2. $Pb(OH) _2$

  3. $Mg(OH) _2$

  4. $Zn(OH) _2$


Correct Option: C
Explanation:

$Mg(OH) _2$ is a basic hydoxide while rest are amphoteric hydroxides.

When aluminium hydroxide is reacted with excess sodium hydroxide, the soluble amphoteric compound is formed. Mark the correct formula. 

  1. $\displaystyle { \left[ { Al\left( OH \right) } _{ 4 } \right] }^{ - }$

  2. $\displaystyle { \left[ { Al\left( OH \right) } _{ 5 } \right] }^{ 2- }$

  3. $\displaystyle { \left[ { Al\left( OH \right) } _{ 6 } \right] }^{ 3- }$

  4. $\displaystyle { \left[ { Al\left( OH \right) } _{ 7 } \right] }^{ 4- }$


Correct Option: A
Explanation:

$Al(OH) _3 + NaOH \rightarrow Na^+ [Al(OH) _4]^-$

 Aluminium hydroxide when reacted with excess sodium hydroxide, the soluble amphoteric compound  formed is sodium tetra hydroxoaluminate (III).

When aluminium hydroxide is reacted with excess ammonium hydroxide, the insoluble compound is formed. Mark the correct formula.

  1. $\displaystyle { \left[ { Al\left( OH \right) } _{ 4 } \right] }^{ 1- }$

  2. $\displaystyle { \left[ { Al\left( OH \right) } _{ 5 } \right] }^{ 2- }$

  3. $\displaystyle { \left[ { Al\left( OH \right) } _{ 6 } \right] }^{ 3- }$

  4. $\displaystyle { \left[ { Al\left( OH \right) } _{ 7 } \right] }^{ 4- }$


Correct Option: C

If the pH of an alkali metal hydroxide is 13.6, the concentration of hydroxide is ;

  1. More than 1 M

  2. Between 0.1 M and 1 M

  3. Between 0.01 M and 1 M

  4. Less than 0.001 M


Correct Option: B
Explanation:
Given that :

$pH = 13.6$

Thus, $pOH = 14 - 13.6$

                     $=0.4$
Hence,
$[O{H^ - }] = lo{g^{ - 1}}( - 0.4)$

               $ = 0.3979$

Therefore the value of $[O{H^ - }]$ is between $0.1M$ and $1M$.

Therefore, the option is B.

A salt contains two atoms of iron, three atoms of sulphur and twelve atoms of oxygen. Identify the corresponding acid and base from which it is formed.

  1. $H _2 SO _4, Fe (OH) _2$

  2. $H _2 SO _3, Fe (OH) _2$

  3. $H _2 SO _3, Fe (OH) _3$

  4. $H _2 SO _4, Fe (OH) _3$


Correct Option: D
Explanation:

$Fe _{2}(SO _{4}) _{3}$ is the salt formed from $Fe(OH) _{3}$ and $H _{2}SO _{4}$. The balanced chemical equation can be written as:
$2Fe(OH) _{3} + 3H _{2}SO _{4} \rightarrow Fe _{2}(SO _{4}) _{3} +6H _{2}O$