Tag: properties of acids and bases

Questions Related to properties of acids and bases

Carbon dioxide reacts with calcium hydroxide to form calcium carbonate and water.
$\displaystyle Ca(OH) 2 + CO _2 \rightarrow CaCO _3 + H _2O$
From this reaction, we can conclude that $CO _2$ is _
________.

  1. acidic

  2. basic

  3. amphoteric

  4. neutral


Correct Option: A
Explanation:

In the given reaction calcium hydroxide which is a base reacts with carbon dioxide to give salt and water. So, carbon dioxide will be acidic in nature because acid and base reacts to give salt and water. nature.

Which of the following represents the products obtained when $MgO$ reacts with $HCl$?

  1. $MgCl _2$ and water

  2. $MgCl$ and water

  3. $MgCl _2$ and hydrogen

  4. $MgCl$ and hydrogen


Correct Option: A
Explanation:

When $MgO$ reacts with $HCl$, the products obtained are $MgCl _2$ and water.


$MgO + 2HCl \rightarrow MgCl _2 + H _2O$

This demonstration can be used to illustrate the characteristic reaction of metals with acid, a single replacement reaction, or to demonstrate the generation of hydrogen gas. The flammability of hydrogen gas can be demonstrated by carefully holding a match or fireplace lighter up to the popping hydrogen bubbles. An audible crackling sound is heard as the hydrogen burns.

Hence, the correct option is $A$

From the reaction of $NaOH$ with sulphur dioxide, what can be concluded about the nature of sulphur dioxide?

  1. It is acidic in nature

  2. It is basic in nature

  3. It is amphoteric in nature

  4. It is neutral in nature


Correct Option: A
Explanation:

We can conclude that sulphr dioxide is acidic in nature as it reacts with a base $(NaOH)$ to form salt and water.
$SO _2 + NaOH \rightarrow NaHSO _3$
$SO _2 + 2NaOH \rightarrow  Na _2SO _3 + H _2O$

When NaOH reacts with $NO _2$, the products obtained are $NaNO _2$ and $NaNO _3$
$2NaOH + 2NO _2 \rightarrow NaNO _2 + NaNO _3 + H _2O$
From this reaction, which nature of $NO _2$ can we conclude?

  1. Acidic

  2. Basic

  3. Amphoteric

  4. Neutral


Correct Option: A
Explanation:

We can conclude that $NO _2$ is acidic in nature as it reacts with a base $(NaOH)$ to form salt and water.

Which of the following product is obtained when dinitrogen trioxide reacts with $KOH$?

  1. $KNO _2$

  2. $KNO _3$

  3. $K _2O$

  4. All of the above


Correct Option: A
Explanation:

The reaction between dinitrogen trioxide and $KOH$ gives $KNO _2$.
$N _2O _3 + 2KOH  \rightarrow 2KNO _2 + H _2O$

The reaction between dinitrogen trioxide and potassium hydroxide gives $KNO _2$.
$N _2O _3 + 2KOH  \rightarrow 2KNO _2 + H _2O$


What can we conclude about the nature of dinitrogen trioxide?

  1. It is acidic oxide

  2. It is basic oxide

  3. It is amphoteric oxide

  4. It is neutral oxide


Correct Option: A
Explanation:
$N _2O _3 + 2KOH  \rightarrow 2KNO _2 + H _2O$

In the above reaction, we can see that dinitrogen trioxide is an acidic oxide, as $N _2O _3$ reacts with a base $(KOH)$ to form salt and water. This is the characteristic of acidic oxide.
Hence, option $A$ is correct.

Which of the following represents the products obtained when $NaOH$ reacts with $NO _2$?

  1. $NaNO _2$

  2. $NaNO _3$

  3. Both of the above

  4. None of the above


Correct Option: C
Explanation:

When NaOH reacts with $NO _2$, the products obtained are $NaNO _2$ and $NaNO _3$
$2NaOH + 2NO _2 \rightarrow NaNO _2 + NaNO _3 + H _2O$

$CuO+(X) \rightarrow CuSO _4+H _2O$ 

Here, $(X)$ is:

  1. $CuSO _4$

  2. $HCl$

  3. $H _2SO _4$

  4. $HNO _3$


Correct Option: C
Explanation:

Acid and base react together, neutralize each other and form salt and water.

$Acid + Base \rightarrow Salt + water$
Here $CuO$ acts as a base and the salt formed is $CuSO _4$, along with formation of water $(H _2O)$.
Since the salt formed is $CuSO _4$, the reacting acid should be sulphate ion ($SO _4^{2-}$) donor, and water would not have been formed if $CuO\  and\  CuSO _4$  would have reacted together. Thus $H _2SO _4$ is the acid that will react with $CuO$ to give $CuSO _4\ and\ H _2O$. The reaction occurs as follows :-
$CuO+H _2SO _4\rightarrow CuSO _4+H _2O$
Hence, the correct answer is option (C).

The equation for the action of a dilute acid on a metal oxide is following:

     Metal oxide + dilute acid $\rightarrow$ Metal salt + Water

  1. True

  2. False


Correct Option: A
Explanation:

Given statement is true. Since water is also formed along with salt .

An example is given below.

$CaO+{ 2HNO } _{ 3 }\rightarrow Ca\left( { NO } _{ 3 } \right) _{ 2 }+{ H } _{ 2 }O$

Chlorine is evolved by the action of:

  1. ${ H } _{ 2 }{ SO } _{ 4 } \ on\ NaCl$

  2. $HCl\ on\ { K } _{ 2 }{ SO } _{ 4 }$

  3. $HCl \ on\ KMN{ O } _{ 4 }$

  4. $HN{ O } _{ 3 }\ on\ KCl$


Correct Option: C
Explanation:

Option $(C)$ is the correct answer.
$Chlorine$ is evolved by the action of $\displaystyle HCl$ on $\displaystyle KMnO _4$
$\displaystyle 2KMnO _4+16HCl \rightarrow 2KCl + 2MnCl _2+8H _2O + 5Cl _2$