Tag: reactions of acids and bases

Questions Related to reactions of acids and bases

When NaOH reacts with $NO _2$, the products obtained are $NaNO _2$ and $NaNO _3$
$2NaOH + 2NO _2 \rightarrow NaNO _2 + NaNO _3 + H _2O$
From this reaction, which nature of $NO _2$ can we conclude?

  1. Acidic

  2. Basic

  3. Amphoteric

  4. Neutral


Correct Option: A
Explanation:

We can conclude that $NO _2$ is acidic in nature as it reacts with a base $(NaOH)$ to form salt and water.

Which of the following product is obtained when dinitrogen trioxide reacts with $KOH$?

  1. $KNO _2$

  2. $KNO _3$

  3. $K _2O$

  4. All of the above


Correct Option: A
Explanation:

The reaction between dinitrogen trioxide and $KOH$ gives $KNO _2$.
$N _2O _3 + 2KOH  \rightarrow 2KNO _2 + H _2O$

The reaction between dinitrogen trioxide and potassium hydroxide gives $KNO _2$.
$N _2O _3 + 2KOH  \rightarrow 2KNO _2 + H _2O$


What can we conclude about the nature of dinitrogen trioxide?

  1. It is acidic oxide

  2. It is basic oxide

  3. It is amphoteric oxide

  4. It is neutral oxide


Correct Option: A
Explanation:
$N _2O _3 + 2KOH  \rightarrow 2KNO _2 + H _2O$

In the above reaction, we can see that dinitrogen trioxide is an acidic oxide, as $N _2O _3$ reacts with a base $(KOH)$ to form salt and water. This is the characteristic of acidic oxide.
Hence, option $A$ is correct.

Which of the following represents the products obtained when $NaOH$ reacts with $NO _2$?

  1. $NaNO _2$

  2. $NaNO _3$

  3. Both of the above

  4. None of the above


Correct Option: C
Explanation:

When NaOH reacts with $NO _2$, the products obtained are $NaNO _2$ and $NaNO _3$
$2NaOH + 2NO _2 \rightarrow NaNO _2 + NaNO _3 + H _2O$

$CuO+(X) \rightarrow CuSO _4+H _2O$ 

Here, $(X)$ is:

  1. $CuSO _4$

  2. $HCl$

  3. $H _2SO _4$

  4. $HNO _3$


Correct Option: C
Explanation:

Acid and base react together, neutralize each other and form salt and water.

$Acid + Base \rightarrow Salt + water$
Here $CuO$ acts as a base and the salt formed is $CuSO _4$, along with formation of water $(H _2O)$.
Since the salt formed is $CuSO _4$, the reacting acid should be sulphate ion ($SO _4^{2-}$) donor, and water would not have been formed if $CuO\  and\  CuSO _4$  would have reacted together. Thus $H _2SO _4$ is the acid that will react with $CuO$ to give $CuSO _4\ and\ H _2O$. The reaction occurs as follows :-
$CuO+H _2SO _4\rightarrow CuSO _4+H _2O$
Hence, the correct answer is option (C).

The equation for the action of a dilute acid on a metal oxide is following:

     Metal oxide + dilute acid $\rightarrow$ Metal salt + Water

  1. True

  2. False


Correct Option: A
Explanation:

Given statement is true. Since water is also formed along with salt .

An example is given below.

$CaO+{ 2HNO } _{ 3 }\rightarrow Ca\left( { NO } _{ 3 } \right) _{ 2 }+{ H } _{ 2 }O$

Chlorine is evolved by the action of:

  1. ${ H } _{ 2 }{ SO } _{ 4 } \ on\ NaCl$

  2. $HCl\ on\ { K } _{ 2 }{ SO } _{ 4 }$

  3. $HCl \ on\ KMN{ O } _{ 4 }$

  4. $HN{ O } _{ 3 }\ on\ KCl$


Correct Option: C
Explanation:

Option $(C)$ is the correct answer.
$Chlorine$ is evolved by the action of $\displaystyle HCl$ on $\displaystyle KMnO _4$
$\displaystyle 2KMnO _4+16HCl \rightarrow 2KCl + 2MnCl _2+8H _2O + 5Cl _2$

Identify acidic salt which can react with one mole of base among the following.

  1. $(NH _{4}) _{2}CO _{3}$

  2. $Na _{2}HPO _{3}$

  3. $NaH _{2}PO _{3}$

  4. $CH _{3}COOK$


Correct Option: C
Explanation:

$H _3PO _3$ is a dibasic acid. In its structure, one oxygen atom is bonded to $P-$ atom via a double bond. $2$ $O-$atoms are bonded to $H-$atoms causing acidity. The third $H$ is directly attached to $P-$ atom responsible for its reducing behavior. 

In $NaH _2PO _3$, one acidic $H$ is replaced by $Na$. Only one $H$ is left which causes the acidic behavior in the salt and hence, will react with one mole of base.