Tag: melde's experiment

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In Melde's experiment, eight loops are formed with a tension of $0.75\space N$. If the tension is increased to four times then the number of loops produces will be

  1. $2$

  2. $4$

  3. $8$

  4. $16$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$Tp^2=constant$
$T _1P _1^2=T _2p _2^2$
$\dfrac{T _2}{T _1}=\dfrac{p _1^2}{p _2^2}$
$\Rightarrow \dfrac{p _1^2}{p _2^2}=4\Rightarrow p _2^2=\dfrac{p _1^2}{4}$
$\Rightarrow p _2^2=\dfrac{64}{4}=16$
$\Rightarrow p _2=4$

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Periodic vibrations of decreasing amplitude are called

  1. Over Vibrations

  2. Critical Vibrations

  3. Damped Vibrations

  4. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Damped vibrations occur when an oscillating system loses energy over time due to resistive forces like friction or air resistance, causing the amplitude to decrease.

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In Melde's experiment, when the tension is 100 g and the tuning fork vibrates at right angles to the direction of the string, 4 loops are produced. If now, the tuning fork is set to vibrate along the string, what additional weight will make the string vibrate in 1 loop? 

  1. 400 g

  2. 300 g

  3. 200 g

  4. 100 g
Reveal answer Fill a bubble to check yourself
A Correct answer
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In Melde's experiment the position is changed from parallel to perpendicular. To get same number of loops, What should be the new length if original length is $l$? (Tension in the string is kept constant) 

  1. $2l$

  2. $l/2$

  3. $4l$

  4. $l/4$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

In perpendicular mode, f = (p/2L) * sqrt(T/m). In parallel mode, f = (p/L) * sqrt(T/m). To keep the same number of loops p and same frequency f, the length L must change. Setting (p/2L1) * sqrt(T/m) = (p/L2) * sqrt(T/m) results in L2 = 2 * L1.

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In Melde's experiment four loops were formed on a string under tension T. When the tension in the string was increased by $3g$, two loops were observed. The original tension T in the string is :

  1. $2 g$

  2. $1 g$

  3. $3 g$

  4. $4 g$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Frequency f is proportional to sqrt(T). In perpendicular mode, f = (p/2L) * sqrt(T/m). Thus, p * sqrt(T) = constant. Initially, 4 * sqrt(T) = 2 * sqrt(T + 3). Squaring both sides: 16T = 4(T + 3) -> 16T = 4T + 12 -> 12T = 12 -> T = 1g.

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In Meldes experiment, the tuning fork is arranged in the parallel position. During $200$ vibrations of the tuning fork, the string ccompletes vibrations

  1. $200$

  2. $100$

  3. $50$

  4. $25$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

In the parallel position, the string completes one full vibration for every one vibration of the tuning fork, because the tension is varied at twice the frequency of the fork.

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If there are six loops for 1 m length in transverse mode of Melde's experiment., the no. of loops in longitudinal mode under otherwise identical condition would be

  1. 3

  2. 6

  3. 12

  4. 8
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

One cycle of up and down vibration for transverse waves on the string is two cycles of string tension increase and decrease. The tension is maximum both at the loops’ maximum up position and again at maximum down position. Therefore, in longitudinal drive mode, since the string tension increases and decreases once per tuning fork vibration, it takes one tuning fork vibration to move the string loop to maximum up position and one to move it to maximum down position. This is two tuning fork vibrations for one up and down string vibration, so the tuning fork frequency is half the string frequency.
Hence, the number of loops in longitudinal mode(tuning fork) is half of that of transverse mode(string).

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In Melde's experiment, the string vibrates in seven segments under tension of $9\space gm-wt$. If string is to be vibrated in three segments then the tension required will be

  1. $1.4\space gm$-$wt$

  2. $13\space gm$-$wt$

  3. $49\space gm$-$wt$

  4. $61\space gm$-$wt$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
The frequency is the same before and after changing the Tension and the number of loops.
From the formula $f = \dfrac{n}{2L}\sqrt{(T/m)}$, we get
$\dfrac{7}{2L}\sqrt{(9/m)} = \dfrac{3}{2L}\sqrt{(T'/m)}$
=>$T' = 49 gm-wt$
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In Melde's experiment, frequency can _______ by ________number of loops of the  string.

  1. increase ,increasing

  2. increase, decreasing

  3. decrease, increasing

  4. decrease, decreasing
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

From the formula f = (p/2L) * sqrt(T/m), increasing the number of loops p increases the frequency f, assuming other variables remain constant.

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The  apparatus of Melde's experiment can be used to test the relationship between 
A. Tension
B. Mass per unit length 
C. Frequency
D. Wavelength
Choose the most appropriate option among the following?

  1. A, B only

  2. A, C only

  3. A,B,C only

  4. All of the above
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Melde's experiment demonstrates the relationship between frequency, tension, mass per unit length, and wavelength (via loop length) in a vibrating string.