Tag: electromagnetic induction and alternating currents

Questions Related to electromagnetic induction and alternating currents

The inductance is measured in 

  1. Ohm

  2. Farad

  3. henery

  4. None of these


Correct Option: C

if the length and area of cross section of an inductor remain same but the number of turns is doubled its self inductance will become:

  1. half

  2. four time

  3. double

  4. one- fourth


Correct Option: B

The SI unit of inductance, the henry, can be written as :

  1. weber / ampere

  2. volt second / ampere

  3. joule / ampere$^2$

  4. ohm second


Correct Option: A,B,C,D
Explanation:

$ L\dfrac{dI}{dt} = emf = \dfrac{d\phi}{dt}$


a) $ [L] = weber / ampere $

b) $ [L] = volt.second / ampere $

c) $ Joule = volt \times ampere \times second $

$ \Rightarrow volt \times second = Joule / ampere$

$ \Rightarrow [L] = joule/ ampere^2$

d) $ V = IR \Rightarrow volt = ampere.ohm$

$\Rightarrow [L] = ohm.second$.

If a spark is produced on removing the load from an AC circuit then the element connected in the circuit is

  1. high resistance

  2. high capacitance

  3. high inductance

  4. high impedance


Correct Option: C
Explanation:

On removal of load from the circuit, the circuit suddenly becomes an open circuit.
Thus $ \dfrac{di}{dt} \rightarrow \infty $
For sparking, high voltage must appear across the open ends. This will happen only in case of an inductor as the voltage drop across the inductor is $ L\dfrac{di}{dt} $
Therefore, the circuit has high inductance.

If N is the number of turns in a coil, the value of self-inductance varies are

  1. N$^o$

  2. N

  3. N$^2$

  4. N$^{-2}$


Correct Option: C
Explanation:

Factual question, self inductance is proportional to square of the number of turns in coil.

Which of the following units denotes the dimensions ${M}{L}^{2}/{Q}^{2}$, where ${Q}$ denotes the electric charge?

  1. $Weber$ ($Wb$)

  2. $Wb$$/\mathrm{m}^{2}$

  3. $Henry$ ($H$)

  4. $\mathrm{H}/\mathrm{m}^{2}$


Correct Option: C
Explanation:

Weber $=ML^2T^{-2}I^{-1}$
$=ML^2T^{-2}Q^{-1}T=ML^2T^{-1}Q^{-1}$   ($I=QT^{-1}$)
Henry H is  SI unit of inductance. 
$H=ML^2T^{-2}I^{-2}$     also $I=QT^{-1}$
so $H=ML^2T^{-2}Q^{-2}T^2=ML^2Q^{-2}$

If $N$ is the number of turns in a circular coil then the value of self inductance varies as

  1. ${N}^{0}$

  2. $N$

  3. ${N}^{2}$

  4. ${N}^{-2}$


Correct Option: B
Explanation:

Self inductance depend on the number of turns in a coils $L \propto N$.

A magnetic field of $2\times {10}^{-2}T$ acts at right angles to a coil of area $100{cm}^{2}$ with $50$ turns. The average emf induced in the coil is $0.1V$. When it is removed from the field in $t$ second, the value of $t$ is

  1. $10s$

  2. $0.1s$

  3. $0.01s$

  4. $1s$


Correct Option: B
Explanation:

$e=\cfrac { -\left( { \phi  } _{ 2 }-{ \phi  } _{ 1 } \right)  }{ t } =\cfrac { -\left( 0-NBA \right)  }{ t } =\cfrac { NBA }{ t } $
$ \therefore \quad t=\cfrac { NBA }{ e } =\cfrac { 50\times 2\times { 10 }^{ -2 }\times { 10 }^{ -2 } }{ 0.1 } \quad t=0.1s$

The inductive reactance of a coil of $0.2H$ inductance at a frequency of $60Hz$ is:

  1. $7.54\Omega $

  2. $0.754 \Omega $

  3. $75.4\Omega $

  4. $7.54\times { 10 }^{ -3 }\Omega $


Correct Option: C
Explanation:

${ X } _{ L }=\omega L=2\pi fL$
$=2\times \cfrac { 22 }{ 7 } \times 60\times 0.2=75.4\Omega $

The SI unit of inductance, the henry, can be written as :

  1. Weber ampere$^{-1}$

  2. Volt - s ampere$^{-1}$

  3. Joule ampere$^{-1}$

  4. ohm $s^{-1}$


Correct Option: B
Explanation:

$V=L\dfrac{di}{dt}$

So the unit $L=\dfrac{Vdt}{di}$
so SI unit of L is $Volt-s\,ampere^{-1}$