Tag: heat and thermodynamics

Questions Related to heat and thermodynamics

The molar specific heat capacity varies as $C=C _v + \beta V$ ($\beta$ is a constant). Then the equation of the process for an ideal gas is given as

  1. $T^{\frac{\beta}{RV} }= constant$

  2. $V^{\frac{\beta T}{R}}=constant$

  3. $T^{-\frac{R}{\beta V}}=constant$

  4. $V^{\frac{R}{\beta T}}=constant$


Correct Option: B

$1$ $\mathrm { g }$ of a steam at $100 ^ { \circ } \mathrm { C }$ melts how much ice at $\mathrm { CC }$ (Latent heat of ice $= 80$ cal/gm and latent heat of steam $ = 540 \mathrm { cal/gm }$



  1. $1 gm$

  2. $2gm$

  3. $4 gm$

  4. $8 gm$


Correct Option: D

The temperature of 5  mole of a gas which was held at constant volume was change from ${ 100 }^{ 0 }$ C to $120^{ 0 }$ C the change in internal energy was found to be 80 joules the total heat capacity of the gas at constant volume will be equal to 

  1. 8 J/K

  2. 0.8 J/K

  3. 4.0 J/K

  4. 0.4 J/K


Correct Option: C

When $1\ mole$ of a monoatomic gas expands at constant pressure the ratio of the heat supplied that increases the internal energy of the gas and that used in expansion is

  1. $\dfrac{2}{3}$

  2. $\dfrac{3}{2}$

  3. $0$

  4. $\infty$


Correct Option: B
Explanation:

Heat supplied to one mole of gas in a constant pressure process is given by: $Q = C _{p}\Delta T$
Change in the internal energy of gas is given by:$\Delta U = C _{v}\Delta T$


The ratio of heat that goes into increasing the internal energy is:
$\dfrac{\Delta U}{Q} = \dfrac{C _{v}}{C _{p}} = \dfrac{1}{\gamma}$

For a mono atomic gas $\gamma = \dfrac{5}{3}$
So, $\dfrac{3}{5}$ ratio of heat goes into increasing the internal energy, and the rest goes into expansion work = $\dfrac{2}{5}$ of heat supplied

Hence, the ratio of heat supplied to increase internal energy by heat supplied to do expansion is $ = \dfrac{3}{2}$

One mole of helium is heated at $0^o$C and constant pressure. How much heat is required to increase its volume threefold?

  1. $3820\ cal$

  2. $382\ cal$

  3. $38.2\ cal$

  4. $3.28\ cal$


Correct Option: A
Explanation:

As it is a constant pressure process, using Charles law we get $\displaystyle\frac{V}{T}=constant$. Thus for a threefold increase in volume we get threefold increase in temperature. Thus we get the final temperature as $3(273)=819 K.$ Thus $\Delta T=819-273=546 K$.
Now as helium is a diatomic molecule, its degree of freedom f is 5. Ths we get $C _p$ for it as $(1+\displaystyle\frac{f}{2})R=(1+\frac{5}{2})R=\frac{7}{2}R$.
Thus heat transferred will be given as $\Delta Q=nC _p\Delta T$
or
$\Delta Q=1(\displaystyle\frac{7}{2})(1.987)(546)=3820\  cal$

When an ideal diatomic gas is heated at constant pressure then what fraction of heat given is used to increase internal energy of gas ? 

  1. $\dfrac{2}{5}$

  2. $\dfrac{3}{5}$

  3. $\dfrac{3}{7}$

  4. $\dfrac{5}{7}$


Correct Option: D
Explanation:

For a diatomic gas we have the degree of freedom as 5. 

Thus heat given at constant pressure is given as $nC _p\Delta T=n(1+\displaystyle\dfrac{5}{2})R\Delta T=n\dfrac{7}{2}R\Delta T$. 
The heat given to change the internal energy is $nC _v\Delta T=n\displaystyle\dfrac{5}{2}R\Delta T$. 
The fraction of internal energy thus used is $\dfrac{5}{7}$ 

One mole of a monoatomic gas and one mole of a diatomic gas are mixed together. What is the molar specific heat at constant volume for the mixture ?

  1. $\dfrac{5}{2} R$

  2. $2 R$

  3. $\dfrac{3}{2} R$

  4. $3 R$


Correct Option: B
Explanation:

$C _v$ is given as $\displaystyle\dfrac{f}{2}R$. Here $f$ is the degree of freedom. For monoatomic gas $f=3$ and for diatomic gas $f=5$. 

Thus we get $C _v$ for the mixture as $\displaystyle\dfrac{n _1}{n _1+n _2}(\dfrac{3}{2}R+\dfrac{5}{2}R)=2R$. Here $n _1$ and $n _2$ both are 1.

If water at ${ 0 }^{ \circ  }C.$kept in a container with an open top , is placed in a large evacuated chamber- 

  1. All the water will sported

  2. All the water will French .

  3. Part of the water will vaporize will be formed and reached . equilibrium at the triple point.

  4. ice , water and vapour will be formed and reach equilibrium at the triple points .


Correct Option: A

Equal volumes of monoatomic and diatomic gases of same initial temperature and pressure are mixed. The ratio of the specific heats of the mixture ($C _p/C _v$) will be

  1. $1.53$

  2. $1.52$

  3. $1.5$

  4. $1$


Correct Option: C
Explanation:

$C _p$ for a gas is given as $(1+\displaystyle\dfrac{f}{2})R$ and $C _v$ is given as $\displaystyle\dfrac{f}{2}R$. Here f is the degree of freedom. 


For monoatomic gas it is 3 and for a diatomic gas it is 5. 

Thus, we get $C _p$ for the mixture as $\displaystyle\dfrac{5}{2}R+\dfrac{7}{2}R=6R$ and $C _v$ is given as $\displaystyle\dfrac{3}{2}R+\dfrac{5}{2}R=4R$.

Thus, the ratio $\displaystyle\dfrac{C _p}{C _v}$ is given as $\displaystyle\dfrac{3}{2}=1.5$

For an ideal gas during an adiabatic process $\left ( \frac{T^{1}}{P^{2}} \right )^{\frac{1}{5}}$  = constant.  The molar heat capacity at constant volume of the gas is 

  1. 2.5 R

  2. 0.5 R

  3. 3 R

  4. $\frac{7}{2}R$


Correct Option: A