Tag: complementary angle, supplementary angles and adjcent angles

Questions Related to complementary angle, supplementary angles and adjcent angles

Let the slope of the lines upon which the incident ray and line mirror lie are respectively $5$ and $3$, then the slope of the line upon which the reflected ray lies is 

  1. $1$

  2. $2$

  3. less than $2$

  4. more than $2$


Correct Option: A

If the angle of a triangle are in the ratio of $2:3:4$, find the there angles 

  1. $40^{o}, 60^{o}, 80^{o}$

  2. $20^{o}, 40^{o}, 60^{o}$

  3. $30^{o}, 60^{o}, 90^{o}$

  4. $90^{o}, 180^{o}, 360^{o}$


Correct Option: A
Explanation:

Let the angles of the triangle be $2x,3x, 4x$. 

Then
$2x+3x+4x=180^o$ [ Since sum of the interior angles of a triangle be $180^o$]
or, $9x=180^o$
or, $x=20^o$.
Then the angles of the triangle be $40^o, 60^o, 80^o$.

Say True or False.
The measure of an acute angle $< 90^o$.

  1. True

  2. False


Correct Option: A
Explanation:
By definition acute angle is the angle which are less than $90^o$.
So, the above statement is true

Say True or False.
If $m\angle A=53^o$ and $m\angle B=35^o$, then $m\angle A > m\angle B$.

  1. True

  2. False


Correct Option: A
Explanation:
$True$
$m \angle A=53^ \circ  \ and \ m \angle B=35^ \circ$
$\because 53 \ > \ 35$
$\therefore m \angle A> m \angle B$

An angle which measures $0^{\circ}$ is called

  1. Obtuse

  2. Straight

  3. Zero

  4. Right


Correct Option: C
Explanation:

An angle which measures $ {0}^{o} $ is called zero angle.

A, B, C and D are four angles at a point so that $A+B+C+D=4$ rightangles, outof these A and B are acute angles while C and D are obtuse angles. Which of the following relations may be true?

  1. $A+B=C+D$
  2. $A+C=B+D$
  3. $A+D=B+C$

  1. 2 and 3 only

  2. 1 and 3 only

  3. 1 and 2 only

  4. 3 only


Correct Option: A

An angle which measures $\displaystyle 0^{0}$ is called-

  1. Zero

  2. Obtuse

  3. Right

  4. None of these


Correct Option: A
Explanation:

an angle which measures 0 degree is called a zero angle..

In a $\displaystyle \Delta PQR$ PQ = PR and $\displaystyle \angle Q$ is twice that of $\displaystyle \angle P$ Then $\displaystyle \angle Q$__

  1. 75$\displaystyle ^{\circ}$

  2. 65$\displaystyle ^{\circ}$

  3. 72$\displaystyle ^{\circ}$

  4. 100$\displaystyle ^{\circ}$


Correct Option: C
Explanation:

$\displaystyle \because $ PQ = PR 
$\displaystyle \Rightarrow $ $\displaystyle \angle Q=\angle R$
Given that $\displaystyle \angle Q=2\angle P$
We have
$\displaystyle \angle P+\angle Q+\angle R=180^{\circ}$
$\displaystyle \frac{\angle Q}{2}+\angle Q+\angle Q=180^{\circ}$
$\displaystyle \frac{5}{2}\angle Q=180^{\circ}$
$\displaystyle \angle Q=72^{\circ}$        

Find the angle between the lines 3x + 2y = 6 and x + y = 6

  1. 12$\displaystyle ^{\circ}$ 20'

  2. 11$\displaystyle ^{\circ}$ 19'

  3. 14$\displaystyle ^{\circ}$ 25'

  4. 13$\displaystyle ^{\circ}$ 06'


Correct Option: B
Explanation:

Line  $3x+2y=6$

$=>2y=-3x+6$
$=>y=\frac{-3}{2}x+\frac{6}{2}$
$=>m'=\frac{-3}{2}x$
$\therefore tan\theta _1=\frac{-3}{2}$
$=>\theta _1=tan^{-1}(\frac{-3}{2})$
$=>\theta _1=-56.31$
Line is $x+y=6$
$=>y=x+6$
$=>m _2=-1$
$=>tan\theta _2=-1$
$=>\theta _2=tan^{-1}(-1)$
$=>\theta _2=-45$
Thus, ale between them $=(-45-56.31)$
                                          $=11.31^0$

Find the complement of each of the following angles $24^{\circ}$

  1. $66^{\circ}$

  2. $156^{\circ}$

  3. $36^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the complement angle

$=90^0-\theta$

So,
The complement angle of $24^0$ will be
$=90^0-24^0=66^0$ 

Hence, this is the answer.