Tag: complementary angle, supplementary angles and adjcent angles

Questions Related to complementary angle, supplementary angles and adjcent angles

Find the complement of each of the following angles
$63^{\circ}$

  1. $27^{\circ}$

  2. $54^{\circ}$

  3. $117^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the complement angle

$=90^0-\theta$

So,
The complement angle of $63^0$ will be
$=90^0-63^0=27^0$ 

Hence, this is the answer.

Find the angles in each of the following.
The angle whose complement is one sixth of its supplement

  1. $72^{\circ}$

  2. $32^{\circ}$

  3. $62^{\circ}$

  4. None of these


Correct Option: A
Explanation:

Let the angle be $x^0$.


Supplement angle $=(180^0-x)$

Complement angle $=(90^0-x)$

According to the question,
$\dfrac{1}{6}\times (180^0-x)=(90^0-x)$

$(180^0-x)=6(90^0-x)$

$180^0-x=540^0-6x$

$5x=360^0$

$x=72^0$


Hence, this is the answer.

Find the angles in each of the following.
The angle which is four times its supplement

  1. $144^{\circ}$

  2. $44^{\circ}$

  3. $14^{\circ}$

  4. None of these


Correct Option: A
Explanation:

Let the angle be $x^0$.


According to the question,
Supplement angle $=(180^0-x)\times 4$

So,

$x=720^0-4x$

$5x=720^0$

$x=144^0$


Hence, this is the answer.

Find the angles in each of the following.
The angles whose supplement is four times its complement

  1. $60^{\circ}$

  2. $30^{\circ}$

  3. $120^{\circ}$

  4. None of these


Correct Option: A
Explanation:

Let the angle be $x^0$.


Supplement angle $=(180^0-x)$

Complement angle $=(90^0-x)$

According to the question,
$180^0-x=4(90^0-x)$

$180^0-x=360^0-4x$

$3x=180^0$

$x=60^0$


Hence, this is the answer.

Find the supplement of each of the following angles.
$148^{\circ}$

  1. $32^{\circ}$

  2. $122^{\circ}$

  3. $148^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the supplement angle

$=180^0-\theta$

So,
The supplement angle of $148^0$ will be
$=180^0-148^0=32^0$ 

Hence, this is the answer.

Find the supplement of each of the following angles.
$120^{\circ}$

  1. $60^{\circ}$

  2. $150^{\circ}$

  3. $20^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the supplement angle

$=180^0-\theta$

So,
The supplement angle of $120^0$ will be
$=180^0-120^0=60^0$ 

Hence, this is the answer.

Find the complement of each of the following angles $35^{\circ}$

  1. $55^{\circ}$

  2. $145^{\circ}$

  3. $35^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the complement angle

$=90^0-\theta$

So,
The complement angle of $35^0$ will be
$=90^0-35^0=55^0$ 

Hence, this is the answer.

Find the supplement of the given angle.
$100^{\circ}$

  1. $80^{\circ}$

  2. $40^{\circ}$

  3. $30^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the sum of the supplement angles

$=180^0$

So,
The supplement angle of $100^0$ will be
$=180^0-100^0=80^0$ 

Hence, this is the answer.

Find the complement of each of the following angles $20^{\circ}$

  1. $70^{\circ}$

  2. $60^{\circ}$

  3. $110^{\circ}$

  4. None of these


Correct Option: A
Explanation:

We know that the complement angle

$=90^0-\theta$

So,
The complement angle of $20^0$ will be
$=90^0-20^0=70^0$ 

Hence, this is the answer.

Find the angles in each of the following.
The angle which is two times its complement

  1. $60^{\circ}$

  2. $120^{\circ}$

  3. $30^{\circ}$

  4. None of these


Correct Option: A
Explanation:

Let the angle be $x^0$.


According to the question,
Complement angle $=(90^0-x)\times 2$

So,

$x=180^0-2x$

$3x=180^0$

$x=60^0$


Hence, this is the answer.