Tag: mathematics and statistics

Questions Related to mathematics and statistics

The slope and y-intercept of the following line are respectively

$8x-4y-1=0$

  1. $ slope=m=\frac { -1 }{ 2 } \quad and\quad y-intercept=\frac { 1 }{ 4 } . $

  2. $ slope=m=2 \quad and\quad y-intercept=-\frac { 1 }{ 4 } . $

  3. $ slope=m=-\frac { 1 }{ 2 } \quad and\quad y-intercept=-\frac { 1 }{ 4 } . $

  4. $ slope=m=\frac { 1 }{ 2 } \quad and\quad y-intercept=\frac { 1 }{ 4 } . $


Correct Option: B
Explanation:
Given line
$8x-4y-1=0$
Comparing above eq with $y=mx+c$ where m is slope and c is y intercept
Here $m=2,c=-\dfrac{1}{4}$

The slope and y-intercept of the following line are respectively

$5x - 2y = 3$

  1. $ slope=m=-\frac { 5 }{ 2 } \quad and\quad y-intercept=-\frac { 3 }{ 2 } . $

  2. $ slope=m=\frac { 5 }{ 2 } \quad and\quad y-intercept=\frac { 3 }{ 2 } . $

  3. $ slope=m=\frac { 5 }{ 2 } \quad and\quad y-intercept=-\frac { 3 }{ 2 } . $

  4. $ slope=m=-\frac { 5 }{ 2 } \quad and\quad y-intercept=\frac { 3 }{ 2 } . $


Correct Option: C
Explanation:

The given equation is $5x-2y=3$ ........ $(1)$

To obtain the slope and $y-$intercept of the given equation, we write it in slope-intercept form which is 
$y=mx+c$, where $m$ and $c$ are slope and $y-$intercept

From $(1)$,
$5x-2y=3\implies y=\dfrac{5}{2}x - \dfrac{3}{2}$
Comparing it with $y=mx+c$ we get,
slope$=m=\dfrac{5}{2}$ and y-intercept$=c=-\dfrac{3}{2}$
Hence, option C is correct.

The slope and $y$-intercept of the following line are respectively

$5x-8y =-2$

  1. slope $=m=-\dfrac { 5 }{ 8 } $ and $ y$-intercept $=\dfrac { 1 }{ 4 }  $

  2. slope $=m=\dfrac { 5 }{ 8 } $ and $y$-intercept $=-\dfrac { 1 }{ 4 }  $

  3. slope $=m=-\dfrac { 5 }{ 8 }$ and $ y$-intercept $=-\dfrac { 1 }{ 4 }  $

  4. slope $=m=\dfrac { 5 }{ 8 } $ and $ y$-intercept $=\dfrac { 1 }{ 4 }  $


Correct Option: D
Explanation:

$ To\quad obtain\quad the\quad slope\quad and\quad y-intercept\quad of\quad an\quad equation\quad of\quad any\quad form\ write\quad it\quad in\quad slope-intercept\quad form\quad which\quad is\quad y=mx+c.\ Then\quad slope=m\quad and\quad y-intercept=c.\  $
The given equation is: $5x - 8y = -2$
$-8y = -5x - 2$
$y = \dfrac{5}{8}x + \dfrac{2}{8} $
Compare it with general form of equation: $y = mx + c$
m = $\dfrac{5}{8}$, y - intercept = c = $  \dfrac{1}{4}$

For the equation given below, find the the slope and the y-intercept : $\displaystyle 3y=7$

  1. $\displaystyle 0 \ and \ \frac{7}{3}$

  2. $\displaystyle 0 \ and \ -\frac{7}{3}$

  3. $\displaystyle -\frac{7}{3} \ and \ 0$

  4. $\displaystyle \frac{7}{3} \ and \ 0$


Correct Option: A
Explanation:

The equation of any straight line can be written as $ y =

mx + c $, where $m$ is its slope and $c$ is its y - intercept.
$ 3y = 7 $ can be written as $ y = \frac {7}{3} $

Comparing this equation with the standard form of the equation, we get:
$ m = 0 , c =  \frac {7}{3} $

Hence, slope of $ 3y = 7 $ is $ 0 $  and y -intercept is $   \frac {7}{3} $

$ax + by + c = 0$ does not represent an equation of line if ____.

  1. $a = c = 0, b \neq 0$

  2. $b = c = 0, a \neq 0$

  3. $a = b = 0$

  4. $c = 0, a \neq 0, b \neq 0 $


Correct Option: C
Explanation:

$ax+by+c=0$ will represent the equation of line If both or one coefficient of $x$ and $y$ is not equal to $0$.

Therefore, if $a=b=0$ then it will not represent the equation of a line.

Find slope, x-intercept & y-intercept of the line 2x - 3y + 5 = 0

  1. $\dfrac{-5}{2},\dfrac{5}{3},\dfrac{2}{3}$

  2. $\dfrac{-5}{2},\dfrac{5}{3},\dfrac{1}{3}$

  3. $\dfrac{-3}{2},\dfrac{5}{3},\dfrac{2}{3}$

  4. $\dfrac{-5}{2},\dfrac{4}{3},\dfrac{2}{3}$


Correct Option: A

Find the slope and $y$-intercept of the line $2x + 5y = 1$

  1. slope $=$ $-\dfrac{2}{5}$, $y$-intercept $=$ $\dfrac{1}{5}$

  2. slope $=$ $-\dfrac{1}{5}$, $y$-intercept $=$ $\dfrac{1}{5}$

  3. slope $=$ $-\dfrac{2}{3}$, $y$-intercept $=$ $\dfrac{1}{5}$

  4. slope $=$ $-\dfrac{2}{5}$, $y$-intercept $= $ $\dfrac{2}{5}$


Correct Option: A
Explanation:
The slope intercept form of the line is $y=mx+c$, where $m$ is the slope of the line and $c$ is the $y$-intercept.
Change the equation $2x+5y=1$ in slope intercept form:
$2x+5y=1$
$5y=-2x+1$
$y=-\dfrac { 2 }{ 5 } x+\dfrac { 1 }{ 5 }$ 
Hence, the slope of the line $2x+2y=-2$ is $m=-\dfrac { 2 }{ 5 }$ and the $y$-intercept is $\dfrac { 1 }{ 5 }$.

Find the slope and $y$-intercept of the line $-5x + y = 5$.

  1. slope $= 5, y$-intercept $= -5$

  2. slope $= 5, y$-intercept $= -4$

  3. slope $= 5, y$-intercept $= 5$

  4. slope $= 5, y$-intercept $= -1$


Correct Option: C
Explanation:

The slope-intercept form is $y = mx + b$, where $m$ is the slope and $b$ is the $y$-intercept. 

Given straight line $-5x+y=5$ can be written as, $y=5x+5$
Now comparing above equation with slope-intercept form $y=mx+c$

We get, slope $=m = 5$ and $y$-intercept $=c=5$.

Hence, option C is correct.

Find the slope and $y$-intercept of the line $0.2x - y = 1.2$

  1. slope $= 0.2$, $y$-intercept $= -1.2$

  2. slope $= 1.2$, $y$-intercept $= -1.2$

  3. slope $= 0.2$, $y$-intercept $= -2.2$

  4. slope $= 0.2$, $y$-intercept $= -1.3$


Correct Option: A
Explanation:
The slope intercept form of the line is $y=mx+c$, where $m$ is the slope of the line and $c$ is the $y$-intercept.
Change the equation $0.2x-y=1.2$ in slope intercept form:
$0.2x-y=1.2$
$\Rightarrow -y=-0.2x+1.2$
$\Rightarrow y=0.2x-1.2$
Hence, the slope of the line $0.2x-y=1.2$ is $m=0.2$ and the $y$-intercept is $-1.2$.

Find the slope and $y$-intercept of the line $2x + 2y = -2$

  1. slope = 1, y-intercept $= -3$

  2. slope = -1, y-intercept $= -1$

  3. slope = 1, y-intercept $= 3$

  4. slope = 1, y-intercept $= 1$


Correct Option: B
Explanation:
The slope intercept form of the line is $y=mx+c$, where $m$ is the slope of the line and $c$ is the $y$-intercept.
Change the equation $2x+2y=-2$ in slope intercept form:
$2x+2y=-2$
$\Rightarrow 2y=-2x-2$
$\Rightarrow y=-x-1$
Hence, the slope of the line $2x+2y=-2$ is $m=-1$ and the $y$-intercept is $-1$.