The most appropriate relationship between electric field and electric potential is given by
$E = - \nabla V _E$
$V _E = - \nabla E$
$E = \nabla V _E$
$V = - \nabla E$
$\vec{E}=-\dfrac{\partial V}{dx}\hat{i}-\dfrac{\partial V}{dy}\hat {j}-\dfrac{\partial V}{dz}\hat{k}$
Electrostatic potential energy of a shell of radius $10cm.$ When $10C$ charge is distributed over its surface.
$4.5 \times {10^{12}}J$
$5.4 \times {10^8}J$
$4.5 \times {10^9}J$
$5.4 \times {10^6}J$
$U = \dfrac{{k\,Q \cdot Q}}{{2R}}$