Tag: maths

Questions Related to maths

Find the ratio of the following :
The speed of cycle is $15$km per hour to the speed of scooter $30$km per hour.

  1. $1:2$

  2. $1:4$

  3. $2:1$

  4. $4:1$


Correct Option: A
Explanation:

Speed of cycle which is $15km/hr$ to the speed of scooter which is $30km/hr = \cfrac {15 km}{30 km} =\cfrac 12 = 1:2$

The ratio of 4kgs and 16kgs is

  1. $1:\sqrt{2}$

  2. $1: 2$

  3. $1: 4$

  4. $1:8$


Correct Option: C
Explanation:

The ratio gets divided as,
$\dfrac{4}{16}$=$\dfrac{1}{4}$

If A:B =$3 :4$ and B:C =$5:6$, then A:C is

  1. $5 : 9$

  2. $3 : 4$

  3. $1 : 2$

  4. $5 : 8$


Correct Option: D
Explanation:

Given that,  If $A:B=3:4,B:C=5:6$,then$A:C$

Given$ a:b=3:4$  and $b:c= 5:6$  

$a:b::b:c =3:4::5:6$ 

$a:c= 3/4*5/6=5/8$ 


Hence, this is the answer. 

In an office the working hours are 9:30 AM to 4:30 PM and in between 20 minutes are spent on lunch Find the ratio of office hours to the time spent for lunch-

  1. $21:1$

  2. $1:14$

  3. $7:30$

  4. $30:7$


Correct Option: A
Explanation:

Total time in office $ = 9:30  to  4:30  = 7  hours  $

Ratio of two quantities can be found when they are of same units.

So, $ 7  hours   = 7 \times 60 = 420  minutes   $
Hence, ratio $ = \dfrac {420  min }{20  min } = 21:1 $

In an office the working hours are 10.30 AM to 5.30 PM and in between 30 minutes are spent on lunch. Find the ratio of office hours to the time spent for lunch.

  1. 7:30`

  2. 1:14

  3. 14:1

  4. 30:7


Correct Option: C
Explanation:

Office hours
$= 10.30$ AM to $5.30$ AM=
 $i.e., 7 hrs = 420 min$.
Lunch time $= 30$ min
$420:30$
14:1

In a class there are 50 boys and 30 girls. The ratio of the number of boys to the number of girls in the class is. 

  1. $80 : 50$

  2. $3 : 5$

  3. $5 : 3$

  4. none


Correct Option: C
Explanation:

To find the ratio of two numbers, we have to consider their fraction. 


Here, it is given that there are $50$ boys and $30$ girls in the class, then the ratio of the number of boys to the number of girls is:

$\dfrac { 50 }{ 30 } =\dfrac { 5 }{ 3 } =5:3$

Hence, the ratio of the number of boys to the number of girls is $5:3$.

If $a:b=5:7$ and $b:c=6:11$, then $a:b:c=$

  1. $55:77:66$

  2. $30:42:77$

  3. $35:49:42$

  4. $50:48:49$


Correct Option: B
Explanation:

$b:c=\begin{pmatrix}6\times\dfrac{7}{6}\end{pmatrix}:\begin{pmatrix}11\times\dfrac{7}{6}\end{pmatrix}=7:\dfrac{77}{6}$
$a:b:c=5:7:\dfrac{77}{6}=30:42:77$

The continued ratio of $4 : 3$ and $5 : 6$ is ____

  1. $4 : 15 : 6$

  2. $4 : 5 : 6$

  3. $20 : 15 : 12$

  4. $20 : 15 : 18$


Correct Option: D
Explanation:

$Ratio 1 = 4 : 3$
$Ratio 2 = 5 : 6$
Multiplying ratio $1$ by antecedent of ratio $2$ and ratio $2$ by consequent of ratio $1$,
Ratio $1 = 20 : 15$
Ratio $2 = 15 : 18$
Thus, for two ratios $a : b$ and $b : c, a : b : c$ is called the continued ratio.
$\therefore 20 : 15 : 18$ is the continued ratio for $4 : 3$ and $5 : 6$.

The continued ratio of $2 : 5$ and $6 : 7$ is _____

  1. $2 : 5 : 7$

  2. $2 : 5 : 6$

  3. $12 : 30 : 35$

  4. $12 : 10 : 42$


Correct Option: C
Explanation:

$R _{1}$ = $2 : 5$
$R _{2}$ =$ 6 : 7$
Multiplying the LCM of the consequent of ratio $1$ and antecedent of ratio $2$, to both the ratios.
$R _1$ = $12 : 30$
$R _2$ = $30 : 35$
Thus, the continued ration for $2 : 5$ and $6 : 7$ is $12 : 30 : 35$

The ratio between the ages of $A$ and $B$ is $2 : 5$. After $8$ years, their ages will be in the ratio $1 : 2$. What is the difference between their present ages?

  1. $20$ years

  2. $22$ years

  3. $24$ years

  4. $25$ years


Correct Option: C
Explanation:

Let $A = 2x; B = 5x$ be the present ages of $A$ and $B$ respectively.
After $8$ years, their ages will be $(2x + 8)$ years and $(5x + 8)$ years respectively.
Therefore, $ (2x + 8) : (5x + 8) : : 1 : 2$
$\Rightarrow  (5x + 8)\times 1 = 2(2x + 8)$
$\Rightarrow x = 8$
Thus difference of their present ages is $5x - 2x = 3x$ i.e., $24$ years.