Tag: maths

Questions Related to maths

The number of matchsticks that can be used to write 23 in Roman system are

  1. 6

  2. 7

  3. 8

  4. 9


Correct Option: B
Explanation:

The Roman numerals are represented by the following letters:

I = 1

V = 5

X = 10

L = 50

C = 100

D = 500

M = 1000

If a numeral is followed by another numeral of lower denomination, the two are added together;

if it is preceded by one of lower denomination, the smaller numeral is subtracted from the greater.

 

23 = XXIII
Therefore, Number of matchsticks required is 7.

Write $14$ in numeral form.

  1. $IV$

  2. $XIV$

  3. $XVI$

  4. $XV$


Correct Option: B
Explanation:

In Roman numeral form, 

$10 = X$
$4 = IV$

$\Rightarrow 14 = XIV$

The difference between Roman numerical M and C is

  1. MC

  2. CM

  3. CX

  4. LX


Correct Option: B
Explanation:

$M=100$

$C=50$
$M-C=100-50=50$
$M-C=M$
So option $B$ is correct.

Convert the given Roman Numerals  'XC' and 'C' in English numeral and then find its difference.

  1. $100$

  2. $20$

  3. $10$

  4. $12$


Correct Option: C
Explanation:

In Roman numeral form, 

$C = 100$
$\Rightarrow XC = 100-10 = 90$

$\therefore$ Difference between $C$ and $XC = 100-90 = 10$ 

In Roman Numeral $C$ has value of

  1. $100$

  2. $50$

  3. $1000$

  4. $500$


Correct Option: A
Explanation:

In Roman numeral form, 

$100 = C$
$50 = L$
$1000 = M$
$500 = D$

Express $19$ in Roman numeral:

  1. $XIX$

  2. $XXI$

  3. $XX$

  4. $XI$


Correct Option: A
Explanation:

In Roman numeral form, 

$10 = X$
$9 = IX$

$\Rightarrow 19 = XIX$

Sumit scored $CDLXXXII$ marks in the annual examination. What is the Hindu-Arabic number for this Roman Number?

  1. $500$

  2. $432$

  3. $482$

  4. $453$


Correct Option: C
Explanation:

Hindu arabic number for $CDLXXXII=482$

Hence the correct answer is option C.

Roman numerical for the greatest three digit number is ________ .

  1. $IXIXIX$

  2. $CMXCIX$

  3. $CMIXIX$

  4. $CMIIC$


Correct Option: B
Explanation:

Greatest $3$ digit number is $999$

Roman numeral for $ 900 = CM$
Roman Numeral for $ 90 = XC$
Roman Numeral for $ 9 = IX$
Roman Numeral for $ 999 = CMXCIX$

Find the value of $MMDCCCLX-MMDCCLIII$.

  1. $XCIX$

  2. $LXII$

  3. $XC$

  4. $CVII$


Correct Option: D
Explanation:

$MMDCCCLX-MMDCCLIII$

= $2860-2753$
= $107$ = $CVII$

Which of the following statements is/are INCORRECT?
(i) Eighty four in Roman numeral is written as $CXXXIV$
(i) There are seven zeroes in $1$ crore.
(iii) There are ten thousand milligrams in $1kg$
(iv) The smallest $4$-digit number formed by using all the digits $4,3,0,8$ without repetition is $3048$

  1. Both (i) and (iii)

  2. Both (i) and (iv)

  3. Only (i)

  4. Only (ii)


Correct Option: A
Explanation:
(i) $84=LXXXIV$
(ii) $1\quad crore=10000000$
(iii) $1kg=1000g=1000\times 10000mg=10000000mg$
(iv) Smallest number formed is $3048$
(i) and (iii) are INCORRECT
Answer : A