Tag: maths

Questions Related to maths

Find HCF by using prime factor method:
$54, 81$ and $99$.

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. $8$

  2. $9$

  3. $10$

  4. $11$

Show answer
Correct Option: B
Explanation:
Factorization of the following.
$54 = 2 \times 3 \times 3 \times 3$
$81 = 3 \times 3 \times 3 \times 3$
$99 = 3 \times 3 \times 11$
Since, the common factor is $3 \times 3$,this implies that
$H.C.F = 3 \times 3$
Hence,the correct option $B$.

HCF of two or more prime numbers is equals to its ___________.

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. $24$.

  2. $2$.

  3. $4$.

  4. $1$.

Show answer
Correct Option: D
Explanation:

We know that

$H.C.F$ of two or more  prime Number is equal to its$ =1$.

Find $HCF$ by finding factors:
$75, 79$ and $89$.

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. $2$

  2. $3$

  3. $1$

  4. $4$

Show answer
Correct Option: C
Explanation:
Factorization of the following 
$75 = 5 \times 5 \times 3\times 1$
$79=1 \times 79$
$89 = 1 \times 89$
Since, the common factor is $1$ this implies that
$HCF = 1$

Hence, the correct option is $C$

Manukaka distribute $96$ marbles among the children of a class in such a way that each child got equal number of marble. In the same class, sameway he also distributed $72$ chocolates. No chocolate and marble is left. How many maximum students are there in this class so that it is possible?

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. $22$

  2. $24$

  3. $26$

  4. $28$

Show answer
Correct Option: B
Explanation:
Factorization of the following.
Maximum students are $ =24$
$72 = (1,2,3,4,6,8,9,12,72)$
$24 = (1,2,3,4,6,8,12,24)$
Since, The common factor is $1,2,3,4$
$H.C.F = 24$
Hence, The correct option is $B$

Find HCF by using prime factor method:
$66$ and $88$.

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. $21$

  2. $23$

  3. $24$

  4. $22$

Show answer
Correct Option: D
Explanation:

Factorization of the following

$66 = 1 \times 3 \times 2 \times 11$
$88 = 1 \times 2 \times 2 \times 2 \times 11$
Since, the common factor is $1,2,11$ this implies that 
$HCF=22$
Hince, the correct option $D$

Find HCF by using prime factor method:
$25$ and $55$.

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. $5$

  2. $3$

  3. $2$

  4. $4$

Show answer
Correct Option: A
Explanation:

Factorization of the following

$25 = 1 \times 5 \times 5$
$55 = 1 \times 5 \times 11$
Since. the common factor is $1,5$ this implies that 
$HCF=5$
Hence, the correct option $A$

What is the HCF of $13$ and $22$?

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. $13$

  2. $22$

  3. $1$

  4. $286$

Show answer
Correct Option: C
Explanation:
Factorization of the following.
HCF=Highest common factor
 so  HCF between $\left( {13,22} \right)$
$ \Rightarrow 13 = 1,13\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, - eq.\left( 1 \right)$
$ \Rightarrow 22 = 1,2,11,22\,\,\,\,\,\,\,\,\,\,\, - eq.\left( 2 \right)$  
$(1)$ &$(2)$ equation common is $1$.
Since, The common factor is $1$. This implies that
 then HCF  is $1$.
Hence, the correct option is $C$.

G.C.D of $4$ and $19$ is _________.

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. $1$

  2. $4$

  3. $19$

  4. $76$

Show answer
Correct Option: A
Explanation:

There is no common factor between $4$ and $19$. Hence, G.C.D. of $4$ and $19$ is $1$.

The two numbers nearest to 10000 which are exactly divisible by each of 2, 3, 4, 5, 6 and 7, are _____.

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. 9660, 10080

  2. 9320, 10080

  3. 9660, 10060

  4. 10340, 10080

Show answer
Correct Option: A
Explanation:

The numbers which are exactly divisible by 2, 3, 4, 5, 6 and 7 are the multiples of the LCM of the given numbers.
$\therefore$  LCM = 2 x 2 x 3 x 5 x 7 = 420
Now, dividing 10000 by 420, we get remainder = 340
$\therefore$  Number just less than 10000 and exactly divisible by the given numbers = 10000 - 340 = 9660
Number just greater than 10000 and exactly divisible by the given numbers = 10000 + (420 - 340) = 10080

If the HCF of 85 and 153 is expressible in the form $85n -153$, then the value of n is:

maths hcf-lcm common factors and hcf hcf highest common factor (h.c.f.)

  1. 3

  2. 2

  3. 4

  4. 1

Show answer
Correct Option: B
Explanation:

$85 = 5 \times  17$

$153 = 3 \times  3 \times 17$
So HCF will be 17
$17 = 85n-153$ from here we get n=2
So the correct answer is option B