Tag: maths

First find the square $13$ and $26.$
$169 = 13 \times 13$
$676 = 26 \times 26$
So, the square of $\dfrac{13}{26}=\dfrac{169}{676}$

Multiply ten's digit with its next number.
$7 \times (7 + 1) = 7 \times 8 = 56 ---(1)$
Find the square of unit's digit: $5$
$5^2 = 25$ ----(2)
Combining (1) and (2), we get
$5625 = 75 \times75$
So, $6$ is the missing number.

$\dfrac{9}{10}$$\times$$\dfrac{9}{10}$ $=$ $\dfrac{81}{100}$

square of $\dfrac{36}{100} = \dfrac{1296}{10000}$

Square of rational number $ = (\dfrac{17 \times 18}{2 \times 9})^2$
                                            

Square of rational number = $(\cfrac{13 \times 12}{10 \times 13})^2$
= $\cfrac{169 \times 144}{100\times 169}$
= $\cfrac{36}{25}$

convert fraction into decimal first.

Multiply ten's digit with its next number.
$9 \times (9 + 1) = 9 \times 10 = 90---(1)$
Find the square of unit's digit: 5
$5^2 = 25$ ----(2)
Combining (1) and (2), we get
$9025 = 95\times95$
So, $9$ is the missing number.

$(\cfrac{9 \times 12}{4\times 3})^2 = (\cfrac{81 \times 144}{16\times 9})$ 
On simplifying, we get
$(\cfrac{9 \times 12}{4\times 3})^2 = 81$