Quantitative Aptitude

Problems on Trains

989 Questions
All Passing a moving person or another train 430 Crossing a platform or bridge 379 Crossing a pole or stationary person 104 Meeting point and post-meeting times 52 Journey time, reduced speed, and schedule conditions 24

Problems on Trains Questions

Multiple choice

இரு இரயில்கள் மணிக்கு 60 கி.மீ மற்றும் 90 கி.மீ வேகத்தில் எதிரெதிர் திசையில் செல்கின்றன. அந்த ரயில்களில் நீளங்கள் முறையே 1.10 கி.மீ மற்றும் 0.9 கி.மீ ஆகும்.எனில் மெதுவாக செல்லும் ரயில் வேகமாக செல்லும் ரயிலை எத்தனை நொடிகளில் கடக்கும்? The two trains go in the opposite direction at speeds of 60 km / h and 90 km respectively. The lengths of those trains are 1.10 km and 0.9 km, respectively. How many seconds will a slow-speed train pass the fast-speed train?

  1. 36 நொடிகள்/36 seconds

  2. 45 நொடிகள்/45 seconds

  3. 48 நொடிகள்/48 seconds

  4. 49 நொடிகள்/49 seconds

  5. இவற்றில் ஏதுமில்லை/None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Relative speed = 60 + 90 = 150 km/h = 150 * 5/18 = 125/3 m/s. Total distance = 1.1 + 0.9 = 2.0 km = 2000 m. Time = Distance / Speed = 2000 / (125/3) = 2000 * 3 / 125 = 16 * 3 = 48 seconds.

Multiple choice

340 மீ நீளமுள்ள ரயில், ஒரு கம்பத்தை 34 நொடிகளில் கடக்கிறது. எனில் 800 மீட்டர் நீளமுள்ள நடைமேடையை கடக்க எவ்வளவு நேரம் ஆகும்? The train, which is 340 m long, crosses a pole in 34 seconds. How long will it take to cross the 800-meter-wide platform?

  1. 100 நொடி / 100 sec

  2. 96 நொடி/ 96 sec

  3. 114 நொடி / 114 sec

  4. 110 நொடி/110 sec

  5. இவற்றில் ஏதுமில்லை/None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Speed of train = 340 m / 34 s = 10 m/s. Time to cross 800 m platform = (Length of train + Length of platform) / Speed = (340 + 800) / 10 = 1140 / 10 = 114 seconds.

Multiple choice

Two trains of length 120m and 80m are running in the same direction with speed of 40 kmph and 50 kmph respectively. Find the time taken by one train to cross the other?

  1. a) 60 sec

  2. b) 72 sec

  3. c) 75 sec

  4. d) 80 sec

  5. e) 65 sec
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

To find the time taken for one train to cross the other when running in the same direction, we first calculate the relative speed, which is 50 - 40 = 10 kmph. Converting this to meters per second gives 10 * 5/18 = 25/9 m/s. The total distance to be covered is the sum of the lengths of the two trains, 120 + 80 = 200 m, so the time taken is 200 / (25/9) = 72 seconds.

Multiple choice

A girl is walking at a speed of 15 km/hr along a railway track. If she is 600m hand of the train which is 300m long and runs at a speed of 180 km/hr in same direction, then what is the time required to pass a girl?

  1. 19.63sec

  2. 32sec

  3. 8.2sec

  4. 28.3sec

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Interpreting “hand” as “ahead,” the train must cover 600 m to reach the girl and another 300 m to pass her. Its relative speed is 180 - 15 = 165 km/hr, or 45.83 m/s, so the time is 900/45.83 ≈ 19.63 seconds.

Multiple choice

A train X travelling at 60 km/h overtakes another train Y, 225 m long, and completely passes it in 72 seconds. If the trains had been going in opposite directions, they would have passed each other in 18 seconds. The length (in m) of X and the speed (in km/h) of Y respectively are:

  1. 245 and 54

  2. 245 and 45

  3. 255 and 36

  4. 255 and 40
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let X length = L, speed = S. Relative speed (same direction) = S - Y_speed = (L + 225) / 72. Relative speed (opposite) = S + Y_speed = (L + 225) / 18. (S+Y)/(S-Y) = 72/18 = 4. S+Y = 4S - 4Y => 3S = 5Y. S = 60 km/h = 60 * 5/18 = 50/3 m/s. 3 * (50/3) = 5Y => Y = 10 m/s = 36 km/h. L+225 = (S-Y) * 72 = (60-36) * 5/18 * 72 = 24 * 5/18 * 72 = 24 * 20 = 480. L = 480 - 225 = 255.

Multiple choice

Ratio between length of two trains is 6 : 7 , while speeds of longer trains and smaller train are 72 km/hr & 108 km/hr respectively. If both trains crosses each other running is opposite direction in 10.4 sec, then find in what time longer train will be cross a platform whose length is 520 m ?

  1. 35sec

  2. 25sec

  3. 45sec

  4. 40sec

  5. 55sec
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Convert speeds: 72 km/h = 20 m/s, 108 km/h = 30 m/s. Relative speed = 50 m/s. Total length = 50 * 10.4 = 520 m. Lengths are 6x and 7x, so 13x = 520, x = 40. Longer train length = 7 * 40 = 280 m. Time to cross 520 m platform = (280 + 520) / 20 = 800 / 20 = 40 seconds.

Multiple choice

The distance between two stations X and Y is 830 km. A train starts from X and runs towards Y at an average speed of S km/hr. Another train starts from Y and runs towards X, 30 minutes before the start of the train from X, at an average speed of (S + 20) km/hr. They cross each other in 3.5 hours from X. What is the value of S (in km/hr)?

  1. 90

  2. 120

  3. 100

  4. 80

  5. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Train Y starts 0.5 hours earlier. In 3.5 hours, Train X travels 3.5S. In 4 hours, Train Y travels 4(S+20). Total distance = 3.5S + 4S + 80 = 830. 7.5S = 750, S = 100.

Multiple choice

Two trains with V1, V2 speeds take 3 seconds to pass one another when going in opposite direction, but take only 2.5 seconds if the speed of any one of it is increase by (its speed) 50%. The time one would take to pass the other when going in the same direction with V1, V2 speeds is ______ sec. [NTSE - Stage - 1, 2018-19, Andhra Pradesh]

  1. 10

  2. 18

  3. 15

  4. 12
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let lengths be L1, L2. V1+V2 = (L1+L2)/3. If one speed increases by 50%, say V1 becomes 1.5V1, then 1.5V1+V2 = (L1+L2)/2.5. This implies 1.5V1+V2 = 1.2(V1+V2), so 1.5V1+V2 = 1.2V1+1.2V2, 0.3V1 = 0.2V2, V2 = 1.5V1. Substituting back, L1+L2 = 3(V1+1.5V1) = 7.5V1. Time same direction = (L1+L2) / |V1-V2| = 7.5V1 / 0.5V1 = 15.