Quantitative Aptitude
Problems on Trains
989 Questions
Problems on Trains Questions
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500
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540
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600
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800
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None of these
A
Correct answer
Explanation
Speed = Distance / Time. Train length = 100m. Crossing a pole (distance = 100m) in 12s, speed = 100/12 = 25/3 m/s. Crossing a platform (distance = 100 + L) in 72s, speed = (100+L)/72. So (100+L)/72 = 25/3. 100+L = 25 * 24 = 600. L = 500m.
B
Correct answer
Explanation
Total distance = 170 + 130 = 300 m. Speed = 40 km/hr = 40 * 5/18 m/s = 200/18 = 100/9 m/s. Time = Distance / Speed = 300 / (100/9) = 300 * 9 / 100 = 27 seconds.
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330 m
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360 m
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390 m
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420 m
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450 m
C
Correct answer
Explanation
Train 1 speed = 220/20 = 11 m/s. Train 2 speed = 11 - (6 * 5/18) = 11 - 1.67 = 9.33 m/s. Relative speed = 11 + 9.33 = 20.33 m/s. Total distance = (L1 + L2) = 20.33 * 30 = 610. L2 = 610 - 220 = 390.
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4 seconds
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6 seconds
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7 seconds
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9 seconds
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11 seconds
C
Correct answer
Explanation
Total distance to cover = 130 + 185 = 315 meters. Relative speed = 90 + 72 = 162 km/h. Convert to m/s: 162 * (5/18) = 45 m/s. Time = Distance / Speed = 315 / 45 = 7 seconds.
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25 m/s
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26 m/s
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25.5 m/s
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27 m/s
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28 m/s
A
Correct answer
Explanation
Let speed be v and train length be L. L + 450 = 20v and L + 700 = 30v. Subtracting equations: 250 = 10v, so v = 25 m/s.
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40 kmph
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50 kmph
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60 kmph
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80 kmph
B
Correct answer
Explanation
Let L be the length of the train and v be its speed. From the first condition, L = v * 18. From the second, L + 250 = v * 36. Substituting the first into the second gives 18v + 250 = 36v, so 18v = 250, v = 250/18 m/s. Converting to kmph: (250/18) * (18/5) = 50 kmph.
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108 km/hr
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92 km/hr
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84 km/hr
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76 km/hr
A
Correct answer
Explanation
Because the train crosses a man, it covers only its own length, 240 m, in 8 seconds. Its speed is 30 m/s, which equals 30 x 18/5 = 108 km/h.
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200 meters
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225 meters
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250 meters
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150 meters
D
Correct answer
Explanation
Speed = 54 km/h = 15 m/s. Distance covered in 30s = 15 * 30 = 450 m. Length of platform = Total distance - Train length = 450 - 300 = 150 m.
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100 kmph and 60 kmph
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200 kmph and 160 kmph
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120 kmph and 80 kmph
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100 kmph and 80 kmph
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None of these
A
Correct answer
Explanation
Let speeds be u and v (km/h). Total length = 400m = 0.4 km. Same direction: (u - v) = 0.4 / (36/3600) = 40 km/h. Opposite direction: (u + v) = 0.4 / (9/3600) = 160 km/h. Solving the system: 2u = 200, u = 100; 2v = 120, v = 60.
D
Correct answer
Explanation
Speed = 80 km/h = 80 * (5/18) m/s = 200/9 m/s. Distance = Speed * Time = (200/9) * 36 = 800 meters. This distance is the sum of the train length and the tunnel length. Train length = 800 - 350 = 450 meters.
C
Correct answer
Explanation
Substitute r = 4 into the equation x = 45r. x = 45 * 4 = 180.
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42 m/s, 38 m/s
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36 m/s, 42 m/s
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38 m/s, 36 m/s
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40 m/s, 36 m/s
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42 m/s, 36 m/s
A
Correct answer
Explanation
Let speeds be v1, v2. Same direction: (v1 - v2) = (130 + 110) / 60 = 4 m/s. Opposite direction: (v1 + v2) = (130 + 110) / 3 = 80 m/s. Solving: 2v1 = 84, v1 = 42; 2v2 = 76, v2 = 38. Option A is 42, 38.
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43 second
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41 second
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45 second
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49 second
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42 second
C
Correct answer
Explanation
Relative speed = 70 + 50 = 120 kmph. Convert to m/s: 120 * 5/18 = 100/3 m/s. Time = Distance / Speed = 1500 / (100/3) = 1500 * 3 / 100 = 45 seconds.
A
Correct answer
Explanation
Current speed = 250m / 10s = 25 m/s. Convert to km/h: 25 * (18/5) = 90 km/h. Required speed = 1350 km / 10 h = 135 km/h. Increase = 135 - 90 = 45. Percentage increase = (45 / 90) * 100 = 50%.