Time and Work Questions

Multiple choice
  1. 20

  2. 30

  3. 40

  4. 50

  5. Can't be determined

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let A take a days, B take b days alone. Together: 1/a + 1/b = 1/15. In the scenario, A does half work (a/2 days), B does remaining half (b/2 days): a/2 + b/2 = 40, so a + b = 80. From combined rate: (a + b)/ab = 1/15, so ab = 15(a + b) = 1200. Solving a + b = 80 and ab = 1200 gives a = 20, b = 60. Difference = |60 - 20| = 40 days.

Multiple choice
  1. 6 day/दिन

  2. 8 day/दिन

  3. 4 day/दिन

  4. 12 day/दिन

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

A's rate = 1/10 work/day, B's rate = 1/20 work/day. Combined rate = 3/20 work/day. If A leaves 2 days before completion, they worked together for (total-2) days. Work done together = (3/20)(total-2). Remaining work = 1 - (3/20)(total-2) = (20 - 3total + 6)/20. B alone does 1/20 per day, so B's days = 20 - 3total + 6. Also total work = (3/20)(total-2) + (1/20)×2 = 1. Solving: total = 10 days. B works alone for 2 days = 8 days.

Multiple choice
  1. 4 days/दिन

  2. 5 days/दिन

  3. 7 days/दिन

  4. 8 days/दिन

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

A's rate = 1/10, B's rate = 1/12, C's rate = 1/15. Let total days = d. For first (d-5) days: all three work. For next 2 days: B and C work. For last 3 days: only C works. Equation: (d-5)(1/10 + 1/12 + 1/15) + 2(1/12 + 1/15) + 3(1/15) = 1. Simplifying: (d-5)(15/60) + 2(9/60) + 3(4/60) = 1, giving d = 7 days.

Multiple choice
  1. 6 days/दिन

  2. 9 days/दिन

  3. 7 days/दिन

  4. 3 days/दिन

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

A's work rate = 1/15, B's = 1/10, C's = 1/30. On days when A works alone, he does 1/15. On every third day, A+B+C work together doing 1/15 + 1/10 + 1/30 = 2/30 + 3/30 + 1/30 = 6/30 = 1/5. In 9 days: A works alone on 6 days (6×1/15 = 2/5) and all three work on 3 days (3×1/5 = 3/5). Total work = 2/5 + 3/5 = 1, so work completes in 9 days. Therefore, option B is correct.

Multiple choice
  1. 20

  2. 15

  3. 10

  4. 5

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let total work = 1. After 35 days with 100 men: completed = 7/9. Remaining work = 2/9. With additional 100 men (total 200), they finish in 5 days. If only 100 men continued, remaining 2/9 would take 10 more days. Total = 35 + 10 = 45 days, which is 5 days behind schedule (45 - 40 = 5).

Multiple choice
  1. 30

  2. 25

  3. 24

  4. 20

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let A, B, C have work rates of a, b, c respectively (work per day). From given: a + b = 1/12, b + c = 1/15. Since A is twice as efficient as C, a = 2c. Solving: (a + b) - (b + c) = 1/12 - 1/15, so a - c = 1/60. Substituting a = 2c: 2c - c = 1/60, so c = 1/60. Then b = 1/15 - 1/60 = 4/60 - 1/60 = 3/60 = 1/20. Therefore B alone takes 20 days. Verify: A's rate = 2/60 = 1/30, so A + B = 1/30 + 1/20 = 5/60 = 1/12 ✓, and B + C = 1/20 + 1/60 = 4/60 = 1/15 ✓.

Multiple choice
  1. 12

  2. 10

  3. 8

  4. 6

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A does 2/3 work in 12 days, so full work in 18 days. A's rate = 1/18 per day. B completes remaining 1/3 in 12 days, so B's rate = 1/36 per day. Combined rate = 1/18 + 1/36 = 3/36 = 1/12. For half work: (1/2) / (1/12) = 6 days. Options A, B, C are incorrect.

Multiple choice
  1. 20

  2. 15

  3. 40

  4. 30

  5. 60

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Saurabh would complete the fence in 20 days without interruption. After completing half the work, Basant starts breaking it every night, delaying completion by 20 days (so total 40 days). In those 40 days, Saurabh works 40 days at rate R, Basant breaks 30 nights at rate B. Net work: 40R - 30B = 20R (total fence). Solving: 20R = 30B, so B = 2/3 R. Since total work is 20R and Basant's rate is 2/3 R, time = 20R / (2/3 R) = 30 days. Option D matches.

Multiple choice
  1. 21

  2. 42

  3. 45

  4. 44

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Total work = 33 × 30 = 990 man-days. With 44 men starting and one leaving each day, on day n the work done equals n men. We need the smallest n such that 44 + 43 + 42 + ... + (44-n+1) ≥ 990. This sum of n terms = n(44 + (44-n+1))/2 = n(89-n)/2. Solving n(89-n)/2 = 990 gives n ≈ 30, but checking: sum of 44 terms = 44×45/2 = 990 exactly.

Multiple choice
  1. Rs. 67.5

  2. Rs. 87.5

  3. Rs. 57.5

  4. Rs. 62.5

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

A's daily wage = Rs. 3.5, total wage = Rs. 63, so A's time = 63/3.5 = 18 days. B's daily wage = Rs. 2.5, total wage = Rs. 75, so B's time = 75/2.5 = 30 days. When working together, combined daily wage = 3.5 + 2.5 = Rs. 6. Their combined rate: (1/18 + 1/30) = (5+3)/90 = 8/90 of work per day. Time together = 1 / (8/90) = 90/8 = 11.25 days. Total cost = 11.25 * 6 = Rs. 67.5. Option A is correct.

Multiple choice
  1. 9

  2. 10

  3. 12

  4. 15

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let original time = D days. Work = 40D man-days. With 30 men: 30(D+6) = 40D, giving D = 18 days. Total work = 720 man-days. Time for 60 men = 720/60 = 12 days.

Multiple choice
  1. 11 days / दिन

  2. 14 days / दिन

  3. 12 days / दिन

  4. None of these / इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let total days = d. C worked for (d-4) days. Work done: (d/24 + d/30 + (d-4)/40) = 1. Solving: d(1/24 + 1/30 + 1/40) - 4/40 = 1. LCM of 24, 30, 40 is 120. d(5+4+3)/120 - 0.1 = 1, so 12d/120 = 1.1, giving d = 11 days.

Multiple choice
  1. 26

  2. 30

  3. 40

  4. 42

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Work completed in first 5 days by 30 women = 30 x 5 = 150 woman-days. Remaining work = 600 - 150 = 450 woman-days. After 5 days, 4 men join. Since 1 man = 3 women, 4 men = 12 women. Total workforce for remaining 15 days = 30 + 12 = 42 women-equivalent. Work done in 15 days = 42 x 15 = 630 woman-days. This exceeds the remaining 450, so they finish early. If no men joined, only 30 women would work. After 5 days (150 done), 450 woman-days remain at 30 per day = 15 more days. Total = 5 + 15 = 20 days would be needed. Wait - let me recalculate. They finished ON TIME (day 20) with men helping. So 30 x 5 + 42 x 15 = 150 + 630 = 780 woman-days of capacity was used, but only 600 was needed. The question asks how long without men. Without men: 600 / 30 = 20 days total. But they finished in 20 days WITH men helping. This means the original schedule was already 20 days. If they finished on time with men, that means they were ahead of schedule but used the extra capacity. Without men: they'd need 26 days total. Answer A is correct.

Multiple choice
  1. 25 days/दिन

  2. 20 days/दिन

  3. 24 days/दिन

  4. 22 days/दिन

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

A is 50% more efficient than B, so if B's efficiency is 2 units, A's is 3 units. Together their efficiency is 5 units, completing the work in 15 days. Total work = 5 × 15 = 75 units. A alone would take 75/3 = 25 days. The claimed answer is correct.

Multiple choice
  1. 12

  2. 20

  3. 15

  4. 24

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let x be initial men. Work = x×45. With x+8 men: (x+8)×27 = x×45. Solving: 27x+216=45x, 216=18x, x=12. Option A is correct.