Quantitative Aptitude
Time, Speed and Distance
2,165 Questions
Time, Speed and Distance Questions
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$60 km/hr$
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$30 km/hr$
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$40 km/hr$
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$50 km/hr$
C
Correct answer
Explanation
Reducing the speed by 1/5 reduces the distance covered in 25 hours by 200 km. Thus, (speed/5) × 25 = 200, giving speed = 40 km/h.
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$336$km
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$682$km
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$598$km
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$630$km
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None of these
D
Correct answer
Explanation
Car speed = 66 km/hr. Time = 528 / 66 = 8 hours. Truck speed = 66 - 24 = 42 km/hr. Truck time = 8 + 7 = 15 hours. Distance = 42 * 15 = 630 km.
C
Correct answer
Explanation
Let v be the speed in mph. Time to travel 5 miles at v is 5/v hours. Time at 72 mph is 5/72 hours. 5/v - 5/72 = 50/3600 hours = 1/72 hours. 5/v = 6/72 = 1/12. v = 60 mph.
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$2$ hours, $90$ km.
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$3$ hours, $180$ km.
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$4$ hours, $270$ km.
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$5$ hours, $90$ km.
B
Correct answer
Explanation
Let t be the time at 60 km/h. Distance = 60t + 75(8-t) = 555. 60t + 600 - 75t = 555. -15t = -45, so t = 3 hours. Distance at 60 km/h is 60 * 3 = 180 km.
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$14$km
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$32$km
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$24$km
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$9$km
C
Correct answer
Explanation
Let x be distance on foot, y on motorcycle. x + y = 25. x/4 + y/32 = 1. Multiply by 32: 8x + y = 32. Subtract x+y=25: 7x = 7, x = 1. Then y = 24 km.
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$30 \ km$
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$40 \ km$
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$45 \ km$
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$48 \ km$
B
Correct answer
Explanation
Let total distance be D. Time for 60% is 0.6D/48. Time for 40% is 0.4D/48. The difference is 0.2D/48 = 10/60 hours. 0.2D = 8. D = 40 km.
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$0.7 km.$
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$0.2 km.$
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$0.6 km.$
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$0.9 km.$
C
Correct answer
Explanation
If the one-way distance is d, the total time is d/3 + d/4 = 21/60 hours. Thus, 7d/12 = 7/20, giving d = 0.6 km.
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$0.7$ km
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$1.5$ km
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$0.9$ km
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$1.6$ km
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$360$ km
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$220$ km
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$180$ km
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$120$ km
A
Correct answer
Explanation
Let d be distance and v be boat speed. Downstream: d/(v+3) = 15. Upstream: d/(v-3) = 20. So 15(v+3) = 20(v-3). 15v + 45 = 20v - 60. 5v = 105, v = 21. Distance d = 15(21+3) = 15 * 24 = 360 km.
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$7 km$
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$6.75\ km$
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$5.42\ km$
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None of these
A
Correct answer
Explanation
Let distance on foot be x. Then distance on cycle is 25-x. Time = x/3.5 + (25-x)/9 = 4. Multiply by 63: 18x + 7(25-x) = 252. 18x + 175 - 7x = 252. 11x = 77. x = 7 km.
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$3.5$ km
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$4.5$ km
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$5.5$ km
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$6.5$ km
D
Correct answer
Explanation
Let d be the distance. Time up = d/2.5. Time down = d/3.25. Total time = 4.6 hours. d(1/2.5 + 1/3.25) = 4.6. d(0.4 + 0.3077) = 4.6. d(0.7077) = 4.6. d = 6.5 km.
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$8.30$ a.m.
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$9$ a.m.
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$9.30$ a.m.
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$10$ am
C
Correct answer
Explanation
The first man has a 1-hour head start, covering 10 km. The relative speed is 30 - 10 = 20 km/hr. Time to overtake = distance / relative speed = 10 km / 20 km/hr = 0.5 hours (30 minutes). Since the second man started at 9 a.m., he overtakes at 9:30 a.m.
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$15$ min early
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$20$ min early
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$5$ min early
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$10$ min early
D
Correct answer
Explanation
Since speed and time are inversely proportional, traveling at 4/5 of the usual speed means the time taken is 5/4 of the usual time. The extra time of 1/4 of the usual time equals 15 minutes, which means the usual time is 60 minutes. Traveling 20% faster (6/5 of the usual speed) means taking 5/6 of the usual time, which is 50 minutes, resulting in arriving 10 minutes early.
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$36$ minutes
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$54$ minutes
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$90$ minutes
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$120$ minutes
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8.00 hours
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7.25 hours
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7.50 hours
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7.45 hours
D
Correct answer
Explanation
Distance = Speed * Time. Distance = 30 km/hr * 6.2 hours = 186 km. Time for train = 186 km / 24 km/hr = 7.75 hours. 7.75 hours is 7 hours and 45 minutes.